我从Access
迁移到Mysql.Codes for vb6
。插入......表中从Mysql中的表2中选择b作为a
mobjCmd.CommandText = "INSERT INTO The123 SELECT The1 AS FirstName FROM schedule"
Set mobjRst = mobjCmd.Execute
而且此查询不适用于Mysql。
我从Access
迁移到Mysql.Codes for vb6
。插入......表中从Mysql中的表2中选择b作为a
mobjCmd.CommandText = "INSERT INTO The123 SELECT The1 AS FirstName FROM schedule"
Set mobjRst = mobjCmd.Execute
而且此查询不适用于Mysql。
mobjCmd.CommandText = "INSERT INTO The123 VALUES("yOUR VALUES")"
MOBJCMD.COMMANDTEXT = "SELECT The1 AS FirstName FROM schedule"
Set mobjRst = mobjCmd.Execute
您必须分上下两CMD
您需要为The123
表
mobjCmd.CommandText = @"INSERT INTO The123 (FirstName) SELECT The1 AS FirstName FROM schedule"
Set mobjRst = mobjCmd.Execute
你意识到嵌件不会返回记录为@Never_Mind
谢谢你hazzik ....它的工作... – Krishnan 2013-03-26 06:53:48
种指出指定列。 – 2013-03-26 04:37:00