我在sql中将两组json数据存储到两个不同的列中。PHP字符串比较,然后突出显示差异
我需要比较两个字符串,然后突出显示不同的字符串。 (我第一次尝试的物品放入一个数组,然后数组差异,不提供我所需要的)
这是第一个字符串{"Pri_ID":"340","SanctionID":"55555","PersonID":"387097","Type":"Athlete","OrgID":"253001","EntryDate":"2013-04-10"},{"Pri_ID":"349","SanctionID":"111222","PersonID":"497625","Type":"Athlete","OrgID":"253001","EntryDate":"2013-04-10"},{"Pri_ID":"334","SanctionID":"111111","PersonID":"420495","Type":"Athlete","OrgID":"253001","EntryDate":"2013-04-10"}"
这里是第二个字符串{"Pri_ID":"337","SanctionID":"111222","PersonID":"497625","Type":"Athlete","OrgID":"253001","EntryDate":"2013-04-10"},{"Pri_ID":"341","SanctionID":"111111","PersonID":"420495","Type":"Athlete","OrgID":"253001","EntryDate":"2013-04-10"},
正如你所看到的,从第二个字符串中删除了一条记录/字符串。我需要显示已被删除的字符串。
这是我迄今所做的:
if (strcmp($str1, $str2)) {
echo $str2;
}
这并不没有剥夺一切出来,并显示字符串