JSF验证器的JUnit测试

Question

我有这个简单的Java方法，用于测试来自JSF页面的输入。

public void validateDC(FacesContext context, UIComponent component, Object value) throws ValidatorException, SQLException 
    { 

     Double d; 
     String s = value.toString().trim(); 

     if (s.length() > 10) 
     { 
       throw new ValidatorException(new FacesMessage(FacesMessage.SEVERITY_ERROR, 
         " Value is too long! (18 digits max)", null)); 
     } 

     try 
     { 
      d = Double.parseDouble(s); 
      if (d < 0) 
      { 
       throw new ValidatorException(new FacesMessage(FacesMessage.SEVERITY_ERROR, 
         " '" + d + "' must be positive number!", null)); 
      } 
     } 
     catch(NumberFormatException nfe) { d = null; } 


     if (d != null) 
     { 


     } 
     else 
     { 
      throw new ValidatorException(new FacesMessage(FacesMessage.SEVERITY_ERROR, 
         s.isEmpty() ? " This field cannot be empty!" : " '" + s + "' is not a number!", null)); 
     } 

    } 

我很感兴趣如何为此验证器编写JUnit测试？我可以简单地调用它并传递参数，但没有返回值。什么是可能的解决方案？

Answer 1

如果使用的是JUnit4，您可以使用此：

@Test(expected=ValidatorException.class) 
public void testValidatorException() { 
//call to trigger the exception 
validateDC(...); 
} 

Answer 2

下面是一些样品我写给你如何可以测试你的方法的简单的想法。

@Test(expected = ValidatorException.class) 
    public void shouldThrowExceptionWhenValueLengthIsGreaterThan10() throws Exception { 
    Validaor validaor = new Validator(); 

    FacesContext context; 
    UIComponent component; 
    Object value;// <-- I don't know what value exactly is. But you have to create one with length less than 10 of its toString() value 
    validaor.validateDC(context,component,value); 

    } 




    @Test 
    public void shouldNotThrowExceptionWhenValueLengthIsLessThan10() throws Exception { 
    Validaor validaor = new Validator(); 

    FacesContext context; 
    UIComponent component; 
    Object value;// create object with length more than 10 chars to of its toString() value 
    validaor.validateDC(context,component,value); 

    } 

希望这有帮助。