首先我显示我当前的查询。左连接选择最后一行和左连接选择一行作为列
SELECT u.id, u.username, GROUP_CONCAT(DISTINCT up.weight) as weights, GROUP_CONCAT(DISTINCT pd.type_change, ':', pd.sum_type_change) as statistics
FROM user u
LEFT JOIN
(SELECT up.weight, up.user_id FROM user_parameter up WHERE up.date BETWEEN '2015-10-10 00:00:00' AND '2017-10-10 00:00:00' ORDER BY up.user_id, up.date ASC) up
ON u.id = up.user_id
LEFT JOIN
(SELECT pd.type_change, count(pd.id) as sum_type_change, dd.user_id FROM diet_day dd
LEFT JOIN product_day pd ON dd.id = pd.diet_day_id
WHERE dd.date_start BETWEEN '2015-10-10 00:00:00' AND '2017-10-10 00:00:00' GROUP BY dd.user_id, pd.type_change) pd
ON u.id = pd.user_id
GROUP BY u.id
这工作得很好,但是我必须第一。减去和up.weight持续的,而不是
GROUP_CONCAT(DISTINCT up.weight)
除此之外,我不得不改变
GROUP_CONCAT(DISTINCT pd.type_change, ':', pd.sum_type_change)
这总是返回字符串如这[1:count,2:count,3:count,4:count] 而不是一列(group_concat)我需要有四个新列。
这是可能的所有这一切在MySQL查询?
不能在普通的SQL返回一个变量的列数。 – Barmar