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我有一个使用四个索引i,j,k和l创建的矩阵。我用下面的方案来创建矩阵,索引矩阵
for i = 1:N
for j = 1:2
for k = 1:2
for l = 1:N
Matrix(l,2(j+2*i-3)+k) = Value
end
end
end
end
当我做到这一点产生变化如下矩阵:
Columns
i = 1 i = 1 i = 1 i = 1 i = 2 i = 2 i = 2 i = 2 ...
j = 1 j = 1 j = 2 j = 2 j = 1 j = 1 j = 2 j = 2 ...
k = 1 k = 2 k = 1 k = 2 k = 1 k = 2 k = 1 k = 2 ...
l = 1
l = 2
.
.
.
不幸的是我索引是错误的,需要去改变它。我不想改变任何计算。我需要将上述矩阵变成一个代码如下:
Columns
l = 1 l = 1 l = 2 l = 2 l = 1 l = 1 l = 2 l = 2 ...
k = 1 k = 2 k = 1 k = 2 k = 1 k = 2 k = 1 k = 2 ...
i = 1 j = 1
i = 1 j = 2
i = 2 j = 1
i = 2 j = 2
.
.
.
换句话说一个代码,看起来像,
for i = 1:N
for j = 1:2
for k = 1:2
for l = 1:N
Matrix(New Index) = Matrix(Old Index)
end
end
end
end
我该怎么办呢?谢谢。
我想有一个很好的理由,为什么你不希望只是再次但正确的指数运行的代码? –
是的,他们是。计算复杂,涉及叠加,多坐标变换和2种高斯积分。 –
我认为,你已经知道正确的指数?换句话说,你知道新指数与旧指数的关系吗? –