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我有错误消息:值org.apache.http.message.BasicHttpResponse不能转换到的JSONObject
误差在执行GET org.json.JSONException:值 有机.apache.http.message.BasicHttpResponse @ java.lang.String类型ed9ee8a不能转换到的JSONObject
和以下的代码:
response = httpclient.execute(httpget);
JSONObject locationObj = new JSONObject(String.valueOf(response));
JSONObject locationInfo = locationObj.getJSONObject("item");
lat = locationInfo.getInt("lat");
lon = locationInfo.getInt("lon");
我不想返回字符串,我想从JSON字符串中获取项目并将它们用于Google地图。
String json = "{\"info\": {" +"\"lat\": " + locationGet.getLat() + ", " + "\"lon\": " + locationGet.getLon() + "} }";