我试图创建一个PHP脚本,它确定服务器(承载下面列出的Java程序的计算机)是否正在运行,如果是,则PHP功能应返回true,否则返回true它返回false。在PHP和Java中使用套接字
这里是服务器:
package darestium.minecraft.server;
import java.io.BufferedReader;
import java.net.*;
import java.io.*;
public class Server {
private static ServerSocket socket;
private static Socket connection;
private static String command = new String();
private static String responseStr = new String();;
private static int port = 4343;
public static void main(String args[]) {
System.out.println("Signal Server is running.");
try {
socket = new ServerSocket(port);
while (true) {
connection = socket.accept();
InputStreamReader inputStream = new InputStreamReader(connection.getInputStream());
DataOutputStream response = new DataOutputStream(connection.getOutputStream());
BufferedReader input = new BufferedReader(inputStream);
command = input.readLine();
response.writeBytes(responseStr);
response.flush();
//response.close();
System.out.println("Running");
}
} catch (IOException e) {
System.out.println("Fail!: " + e.toString());
}
System.out.println("Closing...");
}
}
这里是客户端:
<?
function isRunning() {
$address = 'darestium.dyndns-free.com';
$port = 4343;
$socket = socket_create(AF_INET, SOCK_STREAM, getprotobyname('tcp'));
$message = 'loolololol';
try {
socket_connect($socket, $address, $port);
$status = socket_sendto($socket, $message, strlen($message), MSG_EOF, $address, $port);
if ($status != false) {
return true;
}
return false;
} catch (Exception $e) {
return false;
}
}
?>
以下是显示了PHP页面上的回声出函数的结果的错误信息像这样:
include('server.php');
echo isRunning();
然后,错误消息:
Warning: socket_connect() [function.socket-connect]: unable to connect [0]: No connection could be made because the target machine actively refused it. in C:\Users\darestium\Documents\Portables\xampp\htdocs\darestium\minecraftserver.php on line 9
Notice: Use of undefined constant MSG_EOF - assumed 'MSG_EOF' in C:\Users\darestium\Documents\Portables\xampp\htdocs\darestium\minecraftserver.php on line 11
Warning: socket_sendto() expects parameter 4 to be long, string given in C:\Users\darestium\Documents\Portables\xampp\htdocs\darestium\minecraftserver.php on line 11
我想知道如何解决这个问题。此外,我希望能够发送消息到服务器,任何想法我怎么能做到这一点?我基于此Simple Java TCP Server and PHP Client Problems
注意:我是非常新的套接字和服务器/客户端通信。
编辑:
@VideanuAdrian OK,只是端口转发端口4343,它不再显示了第一个错误,但功能似乎总是返回false,最后两个错误仍然显示。
运行java部分的机器上是否有防火墙?或者如果Java部件位于路由器后面,您是否有端口转发设置? – 2012-04-25 05:34:03
@VideanuAdrian好的,只是端口转发端口4343,它不再显示与第一个错误,但该函数似乎总是返回false,最后两个错误仍然显示。 – Darestium 2012-04-25 05:49:15
哦,另外,错误(第一个)在服务器应用程序关闭时再次显示,并且该函数仍然返回false。 – Darestium 2012-04-25 06:06:33