我想在这样一个URL解析JSON的URL“和空间:无法解析包含在Xcode
NSError *error = nil;
NSString *sampleUrl= @"http://xbmc:[email protected]:8080/jsonrpc?request={\"jsonrpc\":%20\"2.0\",%20\"method\":%20\"VideoLibrary.GetMovies\",%20\"params\":%20{%20\"filter\":%20{\"field\":%20\"playcount\",%20\"operator\":%20\"is\",%20\"value\":%20\"0\"},%20\"limits\":%20{%20\"start\"%20:%200,%20\"end\":%2075%20},%20\"properties\"%20:%20[\"art\",%20\"rating\",%20\"thumbnail\",%20\"playcount\",%20\"file\"],%20\"sort\":%20{%20\"order\":%20\"ascending\",%20\"method\":%20\"label\",%20\"ignorearticle\":%20true%20}%20},%20\"id\":%20\"libMovies\"}";
NSLog(@"%@ ",sampleUrl);
NSData *jsonData = [NSData dataWithContentsOfURL:[NSURL URLWithString:sampleUrl]];
id jsonObjects = [NSJSONSerialization JSONObjectWithData:jsonData options:NSJSONReadingMutableContainers error:&error];
,但我得到一个错误,指出:
Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: 'data parameter is nil'
当我在我的浏览器中复制我的网址: 但我没有试过xcode 我试着改变了设置“减少了22%,并且消除了\:不起作用!
我该如何继续? 谢谢
什么结果ü需要 –
我需要电影例如列表... –
正确的网址是:http://192.168.1.66:8080/jsonrpc?request={"jsonrpc“:”2.0“,”method“:”VideoLibrary.GetMovies“,”params“:{”filter“:{”field “:”playcount“,”operator“:”is“,”value“:”0“},”limits“:{”start“:0,”end“:75},”properties“:[”art“, “评分”,“缩略图”,“playcount”,“文件”],“排序”:{“order”:“升序”,“method”:“label”,“ignorearticle”:true}}, ID“:”libMovies“} –