Mysql减去SUM（金额）DebitAccount从SUM（金额）CreditAccount如果DebitAccount == CreditAccount

需要从贷方和借方账户号码相同的借方总计中减去贷方总计。如果一个值仅存在于借方帐号中，则不需要扣除，只需要获取该值。Mysql减去SUM（金额）DebitAccount从SUM（金额）CreditAccount如果DebitAccount == CreditAccount

一台名为18_7_ChartOfAccounts看起来是这样的：

ID | AccountNumber 
------------- 
1 | 2310 
2 | 2380

另一台名为2_1_journal看起来是这样的：在此基础上总结在Amount列所有值建议创建查询

ID | Amount | DebitAccount | CreditAccount 
------------------------------------------- 
1 | 25.00 | 2310   | 2380 
2 | 200.00 | 2310   | 2380 
3 | 4.00 | 2380   | 2310 
4 | 200.00 | 2380   | 2310 
5 | 50.00 | 2380   | 2620

其中DebitAccount值是一样的。

查询执行以下操作：SUM(Amount) FROM表2_1_journal WHERE DebitAccount表2_1_journal是表一样AccountNumber18_7_ChartOfAccounts

$query_debit_beginning = "SELECT SUM(j.Amount), j.DebitAccount FROM 18_7_ChartOfAccounts AS c LEFT JOIN 2_1_journal AS j ON (c.AccountNumber = j.DebitAccount) group by j.DebitAccount";

不明白其他如何subtrac一个总和。

需要去输出这样

帐户号码是2310，Value为21.00（25 + 200-4-200）

帐户号码是2380，Value为29.00（4 + 200 + 50 - 25-200）

帐户号码是2620，值为-50.00（0（DebitAccount周转） - 50（CreditAccount营业额））

查询应该是以下：

（ SUM(Amount) FROM表2_1_journal WHERE DebitAccount在表2_1_journal相同AccountNumber在表18_7_ChartOfAccounts）

然后

SUM(Amount) FROM表2_1_journal WHERE CreditAccount在表2_1_journal相同AccountNumber在表18_7_ChartOfAccounts

然后

如果DebitAccount等于CreditAccount，则减去SUM(Amount) DebitAccount from SUM(Amount) CreditAccount

不知道如何创建这样的查询。请指教。

基于建议尝试添加选择条件。这里是修改。代码是否正确？尝试并显示为必要的工作

SELECT 
a.AccountNumber, 
IFNULL(d.Amount, 0) - IFNULL(c.Amount, 0) AS Amount 

FROM 18_7_ChartOfAccounts AS a 

LEFT JOIN (
SELECT 
    DebitAccount, RecordYear, 
    SUM(Amount) AS Amount 
FROM 2_1_journal WHERE RecordYear = 2013 
GROUP BY DebitAccount 
) d ON (a.AccountNumber = d.DebitAccount) 

LEFT JOIN (
SELECT 
    CreditAccount, RecordYear, 
    SUM(Amount) AS Amount 
FROM 2_1_journal WHERE RecordYear = 2013 
GROUP BY CreditAccount 
) c ON (a.AccountNumber = c.CreditAccount)

来源

2013-07-01 user2360831

SELECT 
    a.AccountNumber, 
    IFNULL(d.Amount, 0) - IFNULL(c.Amount, 0) AS Amount 

FROM 18_7_ChartOfAccounts AS a 

LEFT JOIN (
    SELECT 
     DebitAccount, 
     SUM(Amount) AS Amount 
    FROM 2_1_journal 
    GROUP BY DebitAccount 
) d ON a.AccountNumber = d.DebitAccount 

LEFT JOIN (
    SELECT 
     CreditAccount, 
     SUM(Amount) AS Amount 
    FROM 2_1_journal 
    GROUP BY CreditAccount 
) c ON a.AccountNumber = d.CreditAccount

来源

2013-07-01 13:57:40 walterquez

似乎代码是使用帐户进行计算的金额。我得到了[[AccountNumber] => 2310 [Amount] => 0 [AccountNumber] => 2380 [Amount] => 0 [AccountNumber] => 2620 [Amount] => -2620' – user2360831

我的不好。更新的查询。 SELECT应该SUM'amount'字段，而不是CreditAccount或DebitAccount。 – walterquez

现在在Mysql中只有一行'1 | 25.00 | 2310 | 2380'和输出是[[AccountNumber] => 2310 [Amount] => 50.00'和[[AccountNumber] => 2380 [Amount] => -75.00'出现它以某种方式总和2倍一个值... – user2360831

像这样的东西应该这样做（未测试）

SELECT a.ID, a.AccountNumber, IFNULL(CreditAmount, 0) - IFNULL(DebitAmount, 0) 
FROM 18_7_ChartOfAccounts a 
LEFT OUTER JOIN (SELECT DebitAccount AS AccountNo, SUM(Amount) AS DebitAmount FROM 2_1_journal GROUP BY DebitAccount) b ON a.AccountNumber = b.AccountNo 
LEFT OUTER JOIN (SELECT CreditAccount AS AccountNo, SUM(Amount) AS CreditAmount FROM 2_1_journal GROUP BY CreditAccount) c ON a.AccountNumber = c.AccountNo 
LEFT OUTER JOIN 2_1_journal c ON a.AccountNumber = c.CreditAccount 
GROUP BY a.ID, a.AccountNumber

来源

2013-07-01 13:47:59 Kickstart

得到错误'SQLSTATE [42S22]：列未找到：1054未知列“一。ID'in'field list''抱歉，看起来是我的错误。将检查我的列名。已经有了值的数组。看起来代码有效。将再次检查 – user2360831

a.ID不应包含在GROUP BY中。发布了类似的答案，但只有GROUP BY用于AccountNumber。 – walterquez

它应该包含在GROUP BY中（如果它正在输出）。 MySQL确实允许它不被包含，但是如果没有包括，大多数SQL的风格都会出错。一般而言，将GROUP BY中的返回字段排除在外并不是一个好习惯。 – Kickstart

Mysql减去SUM（金额）DebitAccount从SUM（金额）CreditAccount如果DebitAccount == CreditAccount

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