Facebook上张贴

Question

这里是我做过什么

• 创建了Facebook的
• 一个应用程序通过登录按钮
• 我现在想登录的用户
• 的所有要求安装在FB SDK使用此威胁提供的代码发布 How to Post to Facebook on iOS 6 in Objective-C using ACAccountStore class

但是没有任何反应。我错过了一步吗？

这是我使用

if([SLComposeViewController isAvailableForServiceType:SLServiceTypeFacebook]) //check if Facebook Account is linked 
    { 
     mySLComposerSheet = [[SLComposeViewController alloc] init]; //initiate the Social Controller 
     mySLComposerSheet = [SLComposeViewController composeViewControllerForServiceType:SLServiceTypeFacebook]; //Tell him with what social plattform to use it, e.g. facebook or twitter 
       [mySLComposerSheet setInitialText:[NSString stringWithFormat:@"Test",mySLComposerSheet.serviceType]]; //the message you want to post 
     [mySLComposerSheet addImage:yourimage]; //an image you could post 
     //for more instance methodes, go here:https://developer.apple.com/library/ios/#documentation/NetworkingInternet/Reference/SLComposeViewController_Class/Reference/Reference.html#//apple_ref/doc/uid/TP40012205 
     [self presentViewController:mySLComposerSheet animated:YES completion:nil]; 
    } 
    [mySLComposerSheet setCompletionHandler:^(SLComposeViewControllerResult result) { 
     NSString *output; 
     switch (result) { 
      case SLComposeViewControllerResultCancelled: 
       output = @"Action Cancelled"; 
       break; 
      case SLComposeViewControllerResultDone: 
       output = @"Post Successfull"; 
       break; 
      default: 
       break; 
     } //check if everything worked properly. Give out a message on the state. 
     UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Facebook" message:output delegate:nil cancelButtonTitle:@"Ok" otherButtonTitles:nil]; 
     [alert show]; 
    }]; 

Answer 1

你setInitialText方法是不正确的代码。 如果您使用stringWithFormat发布serviceType，则需要将其添加到具有“％@”的方法中，否则没有任何内容可以说它显示。

总之，只要改变：

[mySLComposerSheet setInitialText:[NSString stringWithFormat:@"Test",mySLComposerSheet.serviceType]]; 

到：

[mySLComposerSheet setInitialText:[NSString stringWithFormat:@"Test %@",mySLComposerSheet.serviceType]];