如何将jQuery var即$.cookie("FirstName"
传递给FORM
输入值?这是我已经把到目前为止jQuery将var传递给隐藏表单输入
<script type="text/javascript">
jQuery(function($) {
//console.debug($.cookie("FirstName"));
$("#FirstName").value($.cookie("FirstName"));
//console.debug($.cookie("LastName"));
$("#LastName").value($.cookie("LastName"));
//console.debug($.cookie("Email"));
$("#Email").value($.cookie("Email"));
...
FORM
<FORM>
<input name="FirstName" type="hidden" value="">
<input name="LastName" type="hidden" value="">
<input name="Email" type="hidden" value="">
...