在可可中从NSColor获取十六进制值？

Question

有没有人知道是否有可能从可可中的NSColor获得颜色的十六进制值？

Answer 1

实施例使用蓝色NSColor：

NSColor* color = [NSColor blueColor]; 

NSString* hexString = [NSString stringWithFormat:@"%02X%02X%02X", 
(int) (color.redComponent * 0xFF), (int) (color.greenComponent * 0xFF), 
(int) (color.blueComponent * 0xFF)]; 

Answer 2

一个选择是创建一个扩展NSColor

public extension NSColor { 
    func getHexString() -> String { 
     let red = Int(round(self.redComponent * 0xFF)) 
     let grn = Int(round(self.greenComponent * 0xFF)) 
     let blu = Int(round(self.blueComponent * 0xFF)) 
     let hexString = NSString(format: "#%02X%02X%02X", red, grn, blu) 
     return hexString 
    } 
} 

Answer 3

我喜欢DAH的解决方案，我使其成为计算的属性，而不是一个功能：

import Cocoa 

extension NSColor { 

    var hexString: String { 
     let red = Int(round(self.redComponent * 0xFF)) 
     let green = Int(round(self.greenComponent * 0xFF)) 
     let blue = Int(round(self.blueComponent * 0xFF)) 
     let hexString = NSString(format: "#%02X%02X%02X", red, green, blue) 
     return hexString as String 
    } 

} 

Answer 4

由于色彩空间问题而不会崩溃的解决方案：

import Cocoa 

extension NSColor { 

    var hexString: String { 
     guard let rgbColor = usingColorSpaceName(NSCalibratedRGBColorSpace) else { 
      return "FFFFFF" 
     } 
     let red = Int(round(rgbColor.redComponent * 0xFF)) 
     let green = Int(round(rgbColor.greenComponent * 0xFF)) 
     let blue = Int(round(rgbColor.blueComponent * 0xFF)) 
     let hexString = NSString(format: "#%02X%02X%02X", red, green, blue) 
     return hexString as String 
    } 

}