0 我无法直接将name属性作为DOM对象的属性。无法从DOM获取NAME属性 由于从Chrome开发者工具的截图看到，没有物业叫name一个典型div对象： 我失去了一些基本的东西？ 来源 2016-11-14 Old Geezer +1 name获取或设置DOM对象的名称属性; **它仅适用于以下元素**：''，''，''，''，''，''，'<img>'，'<input>'，'<map>'，'<meta> '，'<object>'，'<param>'，'<select>'和'<textarea>'。 来源：https：//developer.mozilla.org/en-US/docs/Web/API/Element/name – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">（Y）（Y）谢谢。 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">@JaromandaX - 请注意[fieldset]（https://www.w3.org/TR/html51/sec-forms.html#ref-for-dom-interface-99）和[embed]（https：// www .w3.org/TR/html51/obsolete.html＃ref-for-htmlembedelement-htmlembedelement-1）在该列表中错误地缺失。 – <span class="text-secondary"> <small> <a rel="noopener" target="_blank" href="https://stackoverflow.com/users/42585/">Alohci</a></span> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> </div> <div class="answer-title"> <span class="text-logo margin-top-sm">A</span> <h2 class="title h4">回答</h2> </div> <div class="item-description text-md markdown-body margin-bottom-40 voidso"> <article class="board-top-1 padding-top-10"> <div class="post-col vote-info"> <span class="count">1<i class="fa fa-thumbs-up"></i></span> <i class="fa fa-check fa-2x"></i> </div> <div class="post-offset"> <div class="answer fmt"> <p>您可以使用<code class="prettyprint-override">element.getAttribute('name')</code>，它会从任何元素返回值<code class="prettyprint-override">name</code>属性。</p> </div> <div class="post-info"> <div class="post-meta row"> <p class="text-secondary col-lg-6"> <span class="source"> <a rel="noopener" target="_blank" href="https://stackoverflow.com/q/40582790">来源</a> </span> </p> <p class="text-secondary col-lg-6"> <span class="float-right date"> <span>2016-11-14 06:08:28</span> </p> <p class="col-12"></p> <p class="col-12"></p></div> </div> <!-- comments --> <div class="comments"> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+1</span></div> <div class="col-lg-11"> <p class="commenttext">谢谢。令人惊讶的是，这种方法很有效，尽管'name'不像Jaromanda X提到的那样是DHTML属性。 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">是的，它的工作原理 - 你的问题是关于我测试过的Developer Tools – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> <div itemprop="comment" class="post-comment"> <div class="row"> <div class="col-lg-1"><span class="text-secondary">+0</span></div> <div class="col-lg-11"> <p class="commenttext">，jQuery的'attr'方法将成功返回我添加到Html标记中的* any *属性的值（包括任何不在规范中的值）。 – <span class="text-secondary"> <small> <span></span> </small> </span> </p> </div> </div> </div> </div> </div> </article> <div> <script async src="https://pagead2.googlesyndication.com/pagead/js/adsbygoogle.js"></script> <ins class="adsbygoogle" style="display:block" data-ad-client="ca-pub-6208739752673518" data-ad-slot="1038284119" data-ad-format="auto" data-full-width-responsive="true"></ins> <script> (adsbygoogle = window.adsbygoogle || []).push({}); </script> </div> </div> <div class="clearfix"> </div> <div class="relative-box"> <div class="relative">相关问题</div> <ul class="relative_list"> <li> 1. <a href="http://www.uwenku.com/question/p-mxovsgwz-op.html" target="_blank" title="如何从Google获取Name属性id_token"> 如何从Google获取Name属性id_token </a> </li> <li> 2. <a 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name获取或设置DOM对象的名称属性; **它仅适用于以下元素**：''，'