C编程猜测游戏

Question

我需要帮助完成我的程序。我似乎无法得到最后一步，当用户输入'y'来玩另一个游戏时，它应该重新开始。如果用户输入'n'那么它应该结束。预先感谢您的任何帮助。以下是我到目前为止的代码。

问题出在这里：
编写一个C程序，与用户一起玩猜数字游戏。

下面是示例运行：

OK, I am thinking of a number. Try to guess it. 

Your guess? 50 
Too high! 
Your guess? 250 
Illegal guess. Your guess must be between 1 and 200. 
Try again. Your guess? 30 
**** CORRECT **** 
Want to play again? y 
Ok, I am thinking of a number. Try to guess it. 
Your guess? 58 
**** CORRECT *** 
Want to play again? n 
Goodbye, It was fun. Play again soon. 

代码：

#include <stdio.h> 
#include <stdlib.h> 
#include <time.h> 

int main() { 
    int i, number, currentGuess, MAX_GUESS = 5; 
    int answer = 'n'; 
    time_t t; 

    srand((unsigned) time(&t)); 
    number = rand() % 200 + 1; 

    printf("Welcome to the game of Guess It! \nI will choose a number between 1 and 200. \nYou will try to guess that number."); 
    printf("If you guess wrong, I will tell you if you guessed too high or too low. \nYou have 5 tries to get the number. \n"); 
    printf("\nOK, I am thinking of a number. Try to guess it. \n"); 

    for (i = 0; i < MAX_GUESS; i++) { 
     printf("\nYour guess?"); 
     scanf("%i", &currentGuess); 

     if (currentGuess > 200) { 
      printf("Illegal guess. Your guess must be between 1 and 200.\n"); 
      printf("Try again.\n "); 
     } 
     else if (currentGuess > number) { 
      printf("Too high!\n"); 
     } 
     else if (currentGuess < number) { 
      printf("Too low!\n"); 
     } 
     else { 
      printf("****CORRECT****\n"); 
      return 0; 
     } 
    } 

    printf("Sorry you have entered the maximum number of tries. \n"); 
    printf("Want to play again? \n"); 
    scanf("%i", &answer); 

    if(answer == 'n') { 
     printf("Goodbye, it was fun. Play again soon.\n"); 
     return 0; 
    } 
    else if (answer != 'n') { 
     printf("Ok, I am thinking of a number. Try to guess it.\n"); 
    } 
} 

Answer 1

这里有一个想法，让你在你的代码做到这一点：

char answer = 'y'; 

do 
{ 
    // ... 
    printf("Want to play again (y/n)? "); 
    scanf(" %c", &answer); 
    // Mind^the space here to discard any 
    // previously read newline character 

} while (answer == 'y'); 

Answer 2

检查下面的代码，你可能想理解代码，而不是仅仅粘贴它。

1. 该代码将执行重复性任务的任务委托给函数。

2. 然后代码依赖函数来说出玩家玩过多少次机会，或者-1表示成功。

3. 并注意getchar()而不是scanf。

注：额外的getchar（）是必要的，因为我不知道，但考虑字符输入取整数输入后提出的一个stdin性格'\n'，这会导致不必要的行为做。所以这是我总是用来解决这种情况的一个小窍门。

，请注意do while循环，这种情况下成为一个典型的例子，其中，应使用do while循环。

另外我用宏来定义MAX_GUESS。这是一个很好的做法。你可能想谷歌它“为什么？”

如果您有任何疑问，请在答案中留言。

#include <stdio.h> 
#include <stdlib.h> 
#include <time.h> 
#include <ctype.h> 

#define MAX_GUESS 5 

int playGame(int number) 
{ 
    printf("\nOK, I am thinking of a number. Try to guess it. \n"); 

    int i, currentGuess; 

    for (i=0; i<MAX_GUESS; i++){ 

     printf("\nYour guess?: "); 
     scanf("%i", &currentGuess); 

     if (currentGuess > 200) { 
      printf("Illegal guess. Your guess must be between 1 and 200.\n"); 
      printf("Try again.\n "); 
     } 

     else if (currentGuess > number) { 
       printf("Too high!\n"); 
     } 


     else if (currentGuess < number) { 
      printf("Too low!\n"); 

     } 

     else { 
      printf("****CORRECT****\n"); 
      return 0; 
     } 
    } 

    return i; 
} 

int main() { 


    int i, number, x; 

    char answer = 'n'; 

    time_t t; 

    srand((unsigned)time(&t)); 

    printf("Welcome to the game of Guess It! \nI will choose a number between 1 and 200. \nYou will try to guess that number."); 
    printf("If you guess wrong, I will tell you if you guessed too high or too low. \nYou have 5 tries to get the number. \n"); 

    do 
    { 
     number = rand()%200+1; 
     x = playGame(number); 

     if (x == MAX_GUESS) 
      printf("Sorry you have entered the maximum number of tries. \n"); 

     printf("Want to play again? \n"); 

     // To flush the newline character 
     getchar(); 
     answer = getchar(); 

    } while (answer != 'n' || answer != 'N'); 

    printf("Goodbye, it was fun. Play again soon.\n"); 

    return 0; 
}