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这里是我的情况：覆盖数组的前n个元素？
a = ["","","","","","","","","",""] #10 elements. Need not always be blank.
b = ["a","b","c","d"]
我想修改a使得a第一n元件用的b的元素，其中n = b.size()代替：
a = ["a","b","c","d","","","","","",""]
那么，有没有一些简单的像a.replace(b)减去截断？
另一种方法是将a.size() - b.size()元素数加到b。