是否有可能执行启动画面来执行HTTP请求,如果此请求执行时间过长(即7-10秒),则中止请求并跳转到主要活动?Android:AsyncTask timeout
下面的代码是我做的,但它不工作 - 超时不起作用,HTTP请求和跳跃正在工作。据我所知,有可能延迟使用AsyncTask
的get()
方法或处理程序。 Get()
方法应该在单独的线程中,但它不起作用。如何做这个任务?
编辑:
public class SplashActivity extends Activity {
private static final String TAG = "SplashActivity";
private Handler handler = new Handler();
private Runnable r;
@Override
protected void onCreate(Bundle savedInstanceState) {
// TODO Auto-generated method stub
super.onCreate(savedInstanceState);
setContentView(R.layout.splash_layout);
if (Helpers.isNetworkConnected(getApplicationContext())) {
Log.d(TAG, "Has Internet");
final DownloadFAQ downloadFAQ = new DownloadFAQ();
new Thread(new Runnable() {
public void run() {
try {
Log.d(TAG, "Timing...");
downloadFAQ.execute().get(1000, TimeUnit.MILLISECONDS);
SplashActivity.this.runOnUiThread(new Runnable() {
public void run() {
Log.d(TAG, "redirect");
redirect();
}
});
} catch (InterruptedException e) {
e.printStackTrace();
} catch (ExecutionException e) {
e.printStackTrace();
} catch (TimeoutException e) {
downloadFAQ.cancel(true);
Log.d(TAG, "Task has benn canceled");
if (downloadFAQ.isCancelled())
redirect();
}
}
}).start();
} else {
r = new Runnable() {
public void run() {
redirect();
}
};
handler.postDelayed(r, 2500);
}
}
private class DownloadFAQ extends AsyncTask<Void, Void, Void> {
@Override
protected Void doInBackground(Void... params) {
Log.d(TAG, "Execute task");
ServerAPI server = new ServerAPI(getApplicationContext());
server.serverRequest(ServerAPI.GET_FAQ, null);
return null;
}
}
private void redirect() {
Intent i = new Intent(SplashActivity.this, TabsActivity.class);
startActivity(i);
finish();
}
@Override
protected void onDestroy() {
super.onDestroy();
handler.removeCallbacks(r);
}
}
为什么要再次调用downloadFAQ.get方法时的AsyncTask仍在运行? –
据我所知,get()方法应该在单独的线程中调用。我试图把这个线程放在doinback的onPostExec主线程中。它看起来并不如此。 – user1376885