SQL语法问题

我正在连接两个表并进行简单的计数，但似乎无法将连接的键变量重命名为更适合这两个表的某些内容，但我一直收到错误“CUSTOMER_NO”在使用它的上下文中是有效的。'我敢肯定，这只是一个小语法错误，但我不能看到它... ...SQL语法问题

SELECT owner_no AS customer_no, 

CASE 
WHEN customer_no BETWEEN 5000 and 5999 THEN 'RENTER' 
WHEN customer_no BETWEEN 6000 and 6999 THEN 'OWNER' 
END AS customer_type 

FROM owner_phone AS op 
INNER JOIN renter_phone AS rp ON op.owner_no = rp.renter_no 

GROUP BY customer_no 
HAVING COUNT(*) > 1;

来源

2011-03-16 Eric

在您的CASE和GROUP BY中使用实际列名称，而不是别名列名称。

CASE 
WHEN owner_no BETWEEN 5000 and 5999 THEN 'RENTER' 
WHEN owner_no BETWEEN 6000 and 6999 THEN 'OWNER' 
END AS customer_type 

FROM owner_phone AS op 
INNER JOIN renter_phone AS rp ON op.owner_no = rp.renter_no 
GROUP BY owner_no 
HAVING Count(*) > 1;

来源

2011-03-16 02:25:01

@jimconstable：你们都对，谢谢。第二个最小问题，如果owner_no和renter_no包含不同的值，我应该使用union函数而不是内部联接正确吗？ – Eric

@Eric，连接owner_no和renter_no。它是建筑物ID，地址还是别的？也许您可以发布一个显示数据库架构的新问题，一些示例数据以及您希望达到的结果，并且我们可以帮助您实现目标。 –

你必须使用OWNER_NO通过您的查询的其余部分，但离开AS CUSTOMER_NO使该列名。

SELECT owner_no AS customer_no, 
CASE 
    WHEN owner_no BETWEEN 5000 and 5999 THEN 'RENTER' 
    WHEN owner_no BETWEEN 6000 and 6999 THEN 'OWNER' 
END AS customer_type 
FROM owner_phone AS op 
INNER JOIN renter_phone AS rp ON op.owner_no = rp.renter_no 
GROUP BY owner_no 
HAVING COUNT(*) > 1;

来源

2011-03-16 02:23:42 jimconstable

回答

相关问题