2013-04-29 45 views
0

我通常会将显示区块放到链接中,以使按钮的所有div都处于活动状态,而不仅仅是文本。但在这种情况下,我需要在ulli中使用display:inline-block,我认为这会禁用其他显示块?如何使所有的li活跃,不仅在里面的文字?li中的活动区域

这里是例子:http://jsfiddle.net/mPGDe/

HTML:

<ul class="menu"> 
    <li><a href="#">first</a></li> 
    <li><a href="#">second</a></li> 
    <li><a href="#l">third</a></li> 
</ul> 

CSS:

ul { 
    margin:40px auto; 
    list-style-type:none; 
    padding:0; 
    text-align: center; 
} 

ul li { 
    position: relative; 
    padding: 7px 17px; 
    margin-right: 10px; 
    background-color: #f2f2f2; 
    display: inline-block; /* does it disable display block? */ 
} 

ul li a { 
    display:block;/* usually to make active all the zone, but here it does not work */ 
} 

回答

1

把垫衬上a而不是li

ul li { 
    position: relative; 
    margin-right: 10px; 
    background-color: #f2f2f2; 
    display: inline-block; /* does it disable display block? */ 
} 

ul li a { 
    padding: 7px 17px; 
    display:block;/* usually to make active all the zone, but here it does not work */ 
} 

演示在http://jsfiddle.net/gaby/mPGDe/1/

+0

是的!而已。所以模拟和清晰。谢谢! – Nrc 2013-04-29 13:48:12