json_encode和json_decode自定义php api不返回json字符串

Question

我最近编写了一个自定义API，用于将数据从多个网站插入到不同服务器的数据库中......但它有一些问题，我不知道它是什么可能是...

这里是我的API代码摘录的样本..

if (function_exists($_GET['method'])) { 
     // function exists, so lets run it. 
     $_GET['method'](); 
    } else { 
     // function does not exist so lets throw an error. 
     $data['respCode'] = "100"; 
     $data['respMsg'] = "The method you have called does not exist. Please reformat your call."; 
     echo json_encode($data); 
    } 

// methods 

function newProspect() { 
    // lets first check for the lead in the database.. 

    $sql = mysql_query("SELECT * FROM leads WHERE email = '".$_POST['email']."' LIMIT 1"); 
    if (mysql_num_rows($sql) >= 1) { 
     // duplicate found, so lets just send the data.. 
     $data = mysql_fetch_assoc($sql); 
     $data['respCode'] = "200"; 
     $data['respMsg'] = "Duplicate Lead. Information echoed."; 
     echo json_encode($data); 
    } else { 
     // no duplicate found, so lets insert the data.. 
     $sql = "INSERT INTO leads SET "; 
     foreach ($_POST as $key => $value) { 
      $sql .= $key." = '".$value."',"; 
     } 
     $sql .= "register_date = '".$rdate."'"; 
     $sql = mysql_query($sql); 
     if (!$sql) { 
      // could not insert the info into the database so lets throw an error. 
      $data['respCode'] = "102"; 
      $data['respMsg'] = "Could not intert into database."; 
      $data['errorMsg'] = mysql_error(); 

      echo json_encode($data); return json_encode($data); 
     } else { 
      // lead was inserted into the database just fine, so lets pass back the data. 
      $id = mysql_insert_id($sql); 
      $sql = mysql_query("SELECT * FROM leads WHERE `idleads` =".$id.""); 
      $data = mysql_fetch_assoc($id); 
      $data['respCode'] = '200'; 
      $data['respMsg'] = "Lead Entered into Database Successfully."; 

      echo json_encode($data); 
     } 
    } 
} 

我还创建了一个类远程API来沟通...这可能是其中问题是..

<?php 

class theApi { 
public $apIdomain = 'http://www.domain.com/api/index.php'; // ie: https://www.mydomain.com/admin/ 

public $APData = array(); 
public $postUrl = ''; 

public function __construct() { 

} 

function method ($meth = 'newProspect') { 
    $this->postUrl = $this->apIdomain."?method=".$meth; 
    return $this; 
} 

function postData($pdata) { 
    foreach ($pdata as $key => $val) { 
     if ($key != 'submit') { 
      $this->APData[$key] = $val; 
     } 
    } 
    return $this; 
} 

function process() { 
    $this->APData['ipaddress'] = ip2long($_SERVER['REMOTE_ADDR']); 

    $ch = curl_init(); 
    curl_setopt($ch, CURLOPT_URL, $this->postUrl); 
    curl_setopt($ch, CURLOPT_HEADER, 0); 
    curl_setopt($ch, CURLOPT_POST, 1); 
    curl_setopt($ch, CURLOPT_POSTFIELDS, $this->APData); 
    curl_setopt($ch, CURLOPT_RETURNTRANSFER,0); 
    curl_setopt($ch, CURLOPT_TIMEOUT,30); 

    $rawresponse = curl_exec($ch); 

    curl_close($ch); 

    return $rawresponse; 

} 
} 

$ap = new theApi(); 

，然后我有我提交的应用程序只是为了测试它...

<?php 
$_method = $_GET['method']; 
require_once("api.php"); 
switch ($_method) { 

    case 'newProspect': 
     $data['name'] = "TestB"; 
    $data['phone'] = "555-555-5555"; 
    $data['email'] = "testB@testerdomain1.com"; 

    $d = $ap->method('newProspect')->postData($data)->process(); 
break; 

case 'updateProspect': 

break; 

case 'saveProject': 
break; 

case 'finishApplication': 
break; 
} 

当我转到http://www.differentdomain.com/api-test/index.php?method=newProspect运行代码我得到在浏览器中输出：{"idleads":"1886","classid":"1","ipaddress":"-949980134","register_date":"0000-00-00 00:00:00","name":"TestB","first_name":null,"last_name":null,"phone":"555-555-5555","phone2":null,"email":"testB@testerdomain1.com","age":null,"zip":null,"traffic_source":"1","affiliateid":null,"sversion":null,"purpose":null,"amount":null,"description":null,"respCode":"200","respMsg":"Duplicate Lead. Information echoed."}

所以API本身就是工作...但我无法在任何地方运行json_decode，它几乎看起来好像CURL没有从API获取数据......任何帮助都非常感谢..我不知道从哪里去这里得到它的工作..

谢谢。变革

新的输出卷曲：

object(stdClass)#2 (20) { ["idleads"]=> string(4) "1886" ["classid"]=> string(1) "1" ["ipaddress"]=> string(10) "-949980134" ["register_date"]=> string(19) "0000-00-00 00:00:00" ["name"]=> string(5) "TestB" ["first_name"]=> NULL ["last_name"]=> NULL ["phone"]=> string(12) "555-555-5555" ["phone2"]=> NULL ["email"]=> string(33) "justinblacktest@testerdomain1.com" ["age"]=> NULL ["zip"]=> NULL ["traffic_source"]=> string(1) "1" ["affiliateid"]=> NULL ["sversion"]=> NULL ["purpose"]=> NULL ["amount"]=> NULL ["description"]=> NULL ["respCode"]=> string(3) "200" ["respMsg"]=> string(36) "Duplicate Lead. Information echoed." }

Answer 1

套装CURL_RETURNTRANSFER到1返回HTTP请求的输出，而不是把它呼应到屏幕上。

$ch = curl_init(); 
curl_setopt($ch, CURLOPT_URL, $this->postUrl); 
curl_setopt($ch, CURLOPT_HEADER, 0); 
curl_setopt($ch, CURLOPT_POST, 1); 
curl_setopt($ch, CURLOPT_POSTFIELDS, $this->APData); 
// Set to 1 
curl_setopt($ch, CURLOPT_RETURNTRANSFER,1); 
curl_setopt($ch, CURLOPT_TIMEOUT,30); 

// now $rawresponse actually contains the JSON retrieved 
// from the API call. 
$rawresponse = curl_exec($ch); 

这是提到in the curl_exec() documentation.