我尽量让自定义响应序列与Alamofire类型“X”不符合协议“ResponseObjectSerializable”
我跟着写自述什么,并创建协议和扩展
@objc public protocol ResponseObjectSerializable {
init?(response: NSHTTPURLResponse, representation: AnyObject)
}
extension Alamofire.Request {
public func responseObject<T: ResponseObjectSerializable>(completionHandler: (NSURLRequest, NSHTTPURLResponse?, T?, NSError?) -> Void) -> Self {
let serializer: Serializer = { (request, response, data) in
let JSONSerializer = Request.JSONResponseSerializer(options: .AllowFragments)
let (JSON: AnyObject?, serializationError) = JSONSerializer(request, response, data)
if response != nil && JSON != nil {
return (T(response: response!, representation: JSON!), nil)
} else {
return (nil, serializationError)
}
}
return response(serializer: serializer, completionHandler: { (request, response, object, error) in
completionHandler(request, response, object as? T, error)
})
}
}
但是当我尝试顺应它,我得到这个错误类型“my_model_class”不符合协议“ResponseObjectSerializable”
我的模型只是一个裸骨类
final class Shot: ResponseObjectSerializable {
required init?(response: NSHTTPURLResponse, representation: AnyObject) {
}
}
将此与Xcode 6.3一起使用,任何人都会遇到这种情况?并知道如何使这项工作?
响应 到@airspeed错误消失,但什么困惑我的是苹果斯威夫特文件中,他们对@objc
协议和符合迅速类的例子并不需要@objc
@objc protocol CounterDataSource {
optional func incrementForCount(count: Int) -> Int
optional var fixedIncrement: Int { get }
}
class TowardsZeroSource: CounterDataSource {
func incrementForCount(count: Int) -> Int {
if count == 0 {
return 0
} else if count < 0 {
return 1
} else {
return -1
}
}
}
错误消失了,但是令我困惑的是在Apple Swift文档中他们有一个关于'@ objc'协议的例子,并且符合它的swift类不需要'@ objc'。我编辑问题并添加代码。 – sarunw