2016-01-29 64 views
1

所以我编写了这个简单的脚本,我知道它不会工作,但脚本本身没有错误地运行,并打电话给www.googleapis.com,所以发生了一些事情。尽管没有看到HTTP响应,但我不知道什么是错误的。它真的在做事情的证据是因为我在中国,当我跑的解释有一段时间,直到我打破手动脚本:如何在python中打印HTTP响应?

OUTPUT WITHOUT PROXY : 

File "youtubeconnect.py", line 30, in <module> 
    execute() 
    File "youtubeconnect.py", line 27, in execute 
    youtube = authenticate() 
    File "youtubeconnect.py", line 15, in authenticate 
    service = build('youtube', 'v3',http=http) 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/oauth2client-1.5.2-py3.5.egg/oauth2client/util.py", line 140, in positional_wrapper 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/google_api_python_client-1.4.2-py3.5.egg/googleapiclient/discovery.py", line 196, in build 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/google_api_python_client-1.4.2-py3.5.egg/googleapiclient/discovery.py", line 242, in _retrieve_discovery_doc 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/oauth2client-1.5.2-py3.5.egg/oauth2client/client.py", line 596, in new_request 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/httplib2-0.9.2-py3.5.egg/httplib2/__init__.py", line 1314, in request 
    (response, content) = self._request(conn, authority, uri, request_uri, method, body, headers, redirections, cachekey) 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/httplib2-0.9.2-py3.5.egg/httplib2/__init__.py", line 1064, in _request 
    (response, content) = self._conn_request(conn, request_uri, method, body, headers) 
    File "/home/xavier/Code/autotube/venv/lib/python3.5/site-packages/httplib2-0.9.2-py3.5.egg/httplib2/__init__.py", line 987, in _conn_request 
    conn.connect() 
    File "/usr/lib/python3.5/http/client.py", line 1229, in connect 
    super().connect() 
    File "/usr/lib/python3.5/http/client.py", line 826, in connect 
    (self.host,self.port), self.timeout, self.source_address) 
    File "/usr/lib/python3.5/socket.py", line 702, in create_connection 
    sock.connect(sa) 

现在,当我通过proxychains和隧道运行解释它工作原理:

ProxyChains-3.1 (http://proxychains.sf.net) 
|DNS-request| www.googleapis.com 
|S-chain|-<>-127.0.0.1:1080-<><>-4.2.2.2:53-<><>-OK 
|DNS-response| www.googleapis.com is 173.194.208.95 
|S-chain|-<>-127.0.0.1:1080-<><>-173.194.208.95:443-<><>-OK 

我是新来的蟒蛇,怎么能得到HTTP错误,谷歌是给我回来时,我尝试错误地连接到API的输出?我的代码:

import httplib2 
import os 
from oauth2client import tools 
from oauth2client.client import AccessTokenCredentials 
#from oauth2client.client import AccessTokenRefreshError 
from googleapiclient.discovery import build 
from googleapiclient.http import MediaFileUpload 
import urllib 
def authenticate(): 
    #scope = "https://www.googleapis.com/auth/youtube.upload" 
    acc_token = "XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX" 
    flow = AccessTokenCredentials(
     acc_token,'Mozilla/5.0 (Windows NT 6.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/41.0.2228.0 Safari/537.36') 
    http = flow.authorize(httplib2.Http()) 
    service = build('youtube', 'v3',http=http) 
    return(service) 


def initialize_upload(youtube): 
    tags = None 
    vid = youtube.videos().insert 
    media_body = MediaFileUpload('1977.mp4', mimetype='video/mp4', 
           chunksize=1024 * 1024, resumable=True) 


def execute(): 
    youtube = authenticate() 
    initialize_upload(youtube) 

execute() 
+0

通常使用oauth2将用户重定向到Google,用户接受认证的范围...然后使用新标记重定向回注册的www站点,您可以使用该标记代表用户采取行动。 –

+0

我正在使用验证的令牌。这是另一种在Google API的任何文档中都没有描述的技术。我知道它连接到api并做了一些事情,但我看不到发生了什么事情,并没有太多例子可以说没有人使用这种技术,但我知道有可能做到这一点,因为我已经看到了报告其他人。 – xavier

回答