6
我有一个列表视图,其中有2个项目,这两个项目是“秒”和“分钟” 当我按“秒”时,我想要一个alertDialogBox打开en show 5 ,10,15,...秒。同样的,当我按分钟当单击listViewItem时显示带单选按钮的alertDialog
事情是这样的:
但我无法实现它,因为我不很了解它是如何工作的。以下是我的代码:
import android.app.Activity;
import android.app.AlertDialog;
import android.content.DialogInterface;
import android.os.Bundle;
import android.view.View;
import android.widget.AdapterView;
import android.widget.AdapterView.OnItemClickListener;
import android.widget.ArrayAdapter;
import android.widget.ListView;
import android.widget.Toast;
public class SettingsActivity extends Activity {
ListView listView = (ListView) findViewById(R.id.settingsList);
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.settings);
String[] values = new String[] { "Seconds", "Minutes" };
// Define a new Adapter
// First parameter - Context
// Second parameter - Layout for the row
// Third parameter - ID of the TextView to which the data is written
// Forth - the Array of data
ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
android.R.layout.simple_list_item_1, android.R.id.text1, values);
// Assign adapter to ListView
listView.setAdapter(adapter);
listView.setOnItemClickListener(new OnItemClickListener() {
public void onItemClick(AdapterView<?> arg0, View arg1,
int position, long arg3) {
AlertDialogView();
}
});
}
private void AlertDialogView() {
final CharSequence[] items = { "15 secs", "30 secs", "1 min", "2 mins" };
AlertDialog.Builder builder = new AlertDialog.Builder(ShowDialog.this);//ERROR ShowDialog cannot be resolved to a type
builder.setTitle("Alert Dialog with ListView and Radio button");
builder.setSingleChoiceItems(items, -1,
new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int item) {
Toast.makeText(getApplicationContext(), items[item],
Toast.LENGTH_SHORT).show();
}
});
builder.setPositiveButton("Yes", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
Toast.makeText(ShowDialog.this, "Success", Toast.LENGTH_SHORT)
.show();
}
});
builder.setNegativeButton("No", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int id) {
Toast.makeText(ShowDialog.this, "Fail", Toast.LENGTH_SHORT)
.show();
}
});
AlertDialog alert = builder.create();
alert.show();
}
}
我改变了代码,我是多么愚蠢......但我仍然在showDialogBox上出现错误。怎么来的?错误是'ShowDialog无法解析为类型' – mXX
如果您发布logcat,以便我们可以看到您正在谈论的内容会更好 – ElefantPhace
不可能,我无法编译,因为我有错误。 Logcat是空的 – mXX