2012-12-22 71 views
1

我有一个Android设备创建一个JSON格式的消息,并将其发送到Tomcat服务器。服务器正在运行一个Java Web应用程序,它接收这个JSON格式的消息,然后处理它。从Android设备发送JSON消息到服务器

我的问题是,当服务器接收到消息时,服务器用看起来像他们的十六进制表示的东西替换某些字符('{','[',''',']'和'}') ,这会导致服务器无法识别邮件的JSON错误

我的问题是,是否有人知道是什么导致了这个问题,以及我会如何解决这个问题(我确定它不是JSON代码,而是方式的消息在被送到方面处理/接收)

这里是我的服务器端代码:

@Override 
protected void processRequest(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { 
    // Setup response 
    PrintWriter out = response.getWriter(); 

    // Store input message as String 
    StringBuilder sb = new StringBuilder(); 
    String message; 

    // Build String 
    while ((message = request.getReader().readLine()) != null) { 
     sb.append(message); 
    } 

    // Full message as String 
    message = sb.toString(); 

    // Convert message to JSON format 
    Gson gson = new Gson(); 
    ImageFeatures features = gson.fromJson(message, ImageFeatures.class); 

    out.println("Normal data: " + features); 
    out.println(); 
} 

这里是我接收到错误:

com.google.gson.JsonSyntaxException: java.lang.IllegalStateException: Expected BEGIN_OBJECT but was STRING at line 1 column 12 
com.google.gson.internal.bind.ReflectiveTypeAdapterFactory$Adapter.read(ReflectiveTypeAdapterFactory.java:176) 
com.google.gson.Gson.fromJson(Gson.java:795) 
com.google.gson.Gson.fromJson(Gson.java:761) 
com.google.gson.Gson.fromJson(Gson.java:710) 
com.google.gson.Gson.fromJson(Gson.java:682) 

这是的Android装置之前产生的JSON格式的消息发送该消息到服务器:

{ 
"image_x_size":800, 
"image_y_size":1600, 
"features": 
    [ 
     {"cart_x":5.0,"cart_y":124.0,"polar_angle":0.0,"polar_dist":0.0,"size":15.0}, 
     {"cart_x":5.0,"cart_y":124.0,"polar_angle":0.0,"polar_dist":0.0,"size":15.0} 
    ] 
} 

这是如何该消息被服务器看到(即,所述message字符串的内容):

%7B+%09%22image_x_size%22%3A800%2C+%09%22image_y_size%22%3A1600%2C+%09%22features%22%3A+%09%09%5B+%09%09%09%7B%22cart_x%22%3A5.0%2C%22cart_y%22%3A124.0%2C%22polar_angle%22%3A0.0%2C%22polar_dist%22%3A0.0%2C%22size%22%3A15.0%7D%2C+%09%09%09%7B%22cart_x%22%3A5.0%2C%22cart_y%22%3A124.0%2C%22polar_angle%22%3A0.0%2C%22polar_dist%22%3A0.0%2C%22size%22%3A15.0%7D+%09%09%5D+%7D+ 

正如你可以看到,该消息字符串具有各种十六进制值来替换某些字符。

很多感谢提前!

编辑:我想我应该有我的Android代码,进一步明晰

HttpClient http_client = new DefaultHttpClient(); 

// Set long timeout limit 
HttpConnectionParams.setConnectionTimeout(http_client.getParams(), 10000); 
HttpConnectionParams.setSoTimeout(http_client.getParams(), 10000); 
HttpResponse response; 

// Setup json_object 
JSONObject json_object = convertImageFeaturesToJSON(data, x, y); 

try { 
HttpPost http_post = new HttpPost(URL_BASE + "/featureuploader"); 

Log.i(TAG, json_object.toString()); 

StringEntity se = new StringEntity(json_object.toString()); 
se.setContentType("application/json; charset=UTF-8"); 
se.setContentEncoding(new BasicHeader(HTTP.CONTENT_TYPE, "application/json; charset=UTF-8")); 

http_post.setEntity(se); 
http_post.setHeader("Accept", "application/json"); 
http_post.setHeader("Content-Type", "application/json"); 

response = http_client.execute(http_post); 

if (response != null) { 
    String response_string = httpResponseToString(response.getEntity().getContent()); 
    if (! response_string.startsWith("Received: <html>")) { 
     Log.i(TAG, "Received: ERROR! - " + response_string.substring(0, 20)); 
    } else { 
     Log.i(TAG, "Received: " + response_string); 
    } 
} else { 
    Log.e(TAG, "Did not receive from server"); 
}    
} catch (Exception e) { 
    Log.e(TAG, "Error: " + e.getMessage()); 
} 

回答

1

这是怎样的消息是由服务器看到...

这是一个网址编码版本你在服务器上看到的JSON。您需要先解码(使用类似URLDecoder的东西),或者以请求解码的方式从请求中检索它。

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