为什么我的变量总是递减到零？

Question

我正在写保龄球脚本的乐趣。我在几个月前完成了一项家庭作业，并使用C++工作，但现在我想用bash来做，因为我更喜欢它。

这里是我的代码：

#!/bin/bash 

for ((teamPlayer = 1 ; teamPlayer <= 5; teamPlayer++)); do 

     for ((bowlingGame = 1; bowlingGame <=3; bowlingGame++)); do 

      read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: " 

        while [[ -z $REPLY ]] || (($REPLY > 300 || $REPLY < 1)) || [[ ! $REPLY =~ [[:digit:]] ]]; do 

         if ((teamPlayer >=1)); then 
          ((bowlingScores +- REPLY)) 
          ((teamPlayer-1)) 
          ((bowlingGame-1)) 
         fi 

         echo -e "\nError Try Again!" 

         read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: " 
        done 

      ((bowlingScores += REPLY)) 

    done 

    ((bowlingScores += average)) 

    echo "The average for player number $teamPlayer is $((average/3))" 

    ((average--)) 

done 

echo "The average score for the team is $((bowlingScores/15))" 

问题是，当我试图让平均每个球员的平均始终为零。我只想在显示平均值时减少平均值。另一个问题是如果我不减少价值，玩家1之后的每个玩家得到一个错误的平均值。

任何帮助将不胜感激。

编辑：得到它的工作。这是新的代码。

#!/bin/bash 

for ((teamPlayer = 1 ; teamPlayer <= 5; teamPlayer++)); do 

     for ((bowlingGame = 1; bowlingGame <=3; bowlingGame++)); do 

      read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: " 


        while [[ -z $REPLY ]] || (($REPLY > 300 || $REPLY < 1)) || [[ ! $REPLY =~ [[:digit:]] ]]; do 

         if ((teamPlayer >=1 || bowlingGame >=1)); then 
          ((bowlingScores +- REPLY)) 
          ((teamPlayer >=1)) && ((teamPlayer-1)) 
          ((bowlingGame-1)) && ((teamPlayer-1)) 
         fi 

         echo -e "\nError Try Again!" 

         read -p "Please enter the bowling score for Player number $teamPlayer in game number $bowlingGame: " 
        done 

      ((bowlingScores += REPLY)) 


      ((average += REPLY)) 

    done 



    echo "The average for player number $teamPlayer is $((average/3))" 

    average=0 

done 

echo "The average score for the team is $((bowlingScores/15))" 

echo $bowlingScores 

Answer 1

这一部分：

((bowlingScores +- REPLY)) 
((teamPlayer-1)) 
((bowlingGame-1)) 

应该是：

((bowlingScores += REPLY)) 
((teamPlayer-=1)) 
((bowlingGame-=1)) 

检查：http://tldp.org/LDP/abs/html/arithexp.html