我有一个圆形的进步脚本在这里找到:http://www.jqueryscript.net/demo/Animated-Circular-Progress-Bar-with-jQuery-Canvas-Circle-Progress/圈进度条不断循环
我把它添加到我的网站,事情是,我周围的页面中间的这些元件(未考虑当页面加载)。我的目的是在用户向下滚动到该位置时显示动画,但是该效果在每个滚动上都保持循环。如何让元素只能在元素进入视图时运行一次,并防止循环和/或重新启动?
这里是我到目前为止的代码: http://jsfiddle.net/1f58u1o5/1/
CSS
.progressbar {
display: inline-block;
width: 100px;
margin: 25px;
}
.circle {
width: 100%;
margin: 0 auto;
margin-top: 10px;
display: inline-block;
position: relative;
text-align: center;
}
.circle canvas { vertical-align: middle; }
.circle div {
position: absolute;
top: 30px;
left: 0;
width: 100%;
text-align: center;
line-height: 40px;
font-size: 20px;
}
.circle strong i {
font-style: normal;
font-size: 0.6em;
font-weight: normal;
}
.circle span {
display: block;
color: #aaa;
margin-top: 12px;
}
HTML
<div style="width:100%;height:500px;"></div>
<h3>Sed scelerisque</h3>
<div class="progressbar">
<div class="circle" data-percent="98"><div></div><p>Quisque's</p></div>
</div>
<div class="progressbar">
<div class="circle" data-percent="30"><div></div><p>Maecenas</p></div>
</div>
<div class="progressbar">
<div class="circle" data-percent="77"><div></div><p>Pellentesque</p></div>
</div>
<div class="progressbar">
<div class="circle" data-percent="49"><div></div><p>Etiam sodales</p></div>
</div>
<div style="width:100%;height:500px;"></div>
的JavaScript
$(document).ready(function($){
function animateElements(){
$('.progressbar').each(function(){
var elementPos = $(this).offset().top;
var topOfWindow = $(window).scrollTop();
var percent = $(this).find('.circle').attr('data-percent');
var percentage = parseInt(percent, 10)/parseInt(100, 10);
if(elementPos<topOfWindow+$(window).height()-30){
$(this).find('.circle').circleProgress({
startAngle: -Math.PI/2,
value: percentage,
thickness: 14,
fill: { color: '#1B58B8' }
}).on('circle-animation-progress', function(event,progress,stepValue) {
$(this).find('div').text(String(stepValue.toFixed(2)).substr(2) + '%');
}).stop();
}
});
}
// Show animated elements
animateElements();
$(window).scroll(animateElements);
});
任何建议S' 非常感谢。