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我想知道为什么这个代码中的akka Actor的接收方法的行为像一个val?为什么在akka中接收Actor方法的行为像val?
import akka.actor.{ ActorRef, ActorSystem, Props, Actor }
import scala.concurrent.duration._
// Define Actor Messages
case class WhoToGreet(who: String)
// Define Greeter Actor
class Greeter extends Actor {
def receive = {
println("in receive")
receiveHandler
}
def receiveHandler: Receive = {
case WhoToGreet(who) => println(s"Hello $who")
}
}
object HelloAkkaScala extends App {
// Create the 'hello akka' actor system
val system = ActorSystem("Hello-Akka")
// Create the 'greeter' actor
val greeter = system.actorOf(Props[Greeter], "greeter")
// Send WhoToGreet Message to actor
greeter ! WhoToGreet("Akka")
greeter ! WhoToGreet("Akka")
greeter ! WhoToGreet("Akka")
//shutdown actorsystem
system.terminate()
}
输出:
in receive
Hello Akka
Hello Akka
Hello Akka
,当它被认为是:
in receive
Hello Akka
in receive
Hello Akka
in receive
Hello Akka
而接收是DEF。
有关这种行为的任何想法,为什么def这里计算像val?
谢谢,但为什么在这[代码](https://www.jdoodle.com/embed/v0/scala/2.12.0/14e)它的行为像一个def? – SaKou
您链接的代码与PartialFunctions完全无关,您可以通过将返回类型更改为Unit来证明这一点。您的方法在PartialFunction之外执行副作用(printlns)。 Akka调用(缓存的)PartialFunction。 –
你可以请,看看上面的代码,我已经将部分类型更改为:type Partial = PartialFunction [Any,Unit] 我看不出差异 – SaKou