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我有以下XML & XSLT,当我用带有IE11的XML打开时,它无法正确呈现。带XSLT的XML在IE11中无法正确显示
<?xml version="1.0"?>
<?xml-stylesheet type="text/xsl" href="StyleSheet.xsl" ?>
<FIXML>
<Header>
<RequestID>ReqID8942</RequestID>
</Header>
<Body>
<Data>
<LimitDetails>
<LimitRefNo>L1</LimitRefNo>
<LimitClassification>ROOT</LimitClassification>
<ParentLimitRefNo></ParentLimitRefNo>
<ApprovedLimit>100.0</ApprovedLimit>
</LimitDetails>
<LimitDetails>
<LimitRefNo>L2</LimitRefNo>
<LimitClassification>ClASSIFICATION1</LimitClassification>
<ParentLimitRefNo>L1</ParentLimitRefNo>
<ApprovedLimit>200.0</ApprovedLimit>
</LimitDetails>
<LimitDetails>
<LimitRefNo>L3</LimitRefNo>
<LimitClassification>CLASSIFICATION2</LimitClassification>
<ParentLimitRefNo>L2</ParentLimitRefNo>
<ApprovedLimit>300.0</ApprovedLimit>
</LimitDetails>
<LimitDetails>
<LimitRefNo>L4</LimitRefNo>
<LimitClassification>CLASSIFICATION3</LimitClassification>
<ParentLimitRefNo>L3</ParentLimitRefNo>
<ApprovedLimit>400.0</ApprovedLimit>
</LimitDetails>
</Data>
</Body>
</FIXML>
和XSL如下:
<?xml version="1.0" encoding="UTF-8"?>
<xsl:transform version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" />
<xsl:template match="@*|node()">
<xsl:copy><xsl:apply-templates select="@*|node()" /></xsl:copy>
</xsl:template>
<xsl:template match="Data">
<xsl:copy>
<LimitDetails>
<Limit>
<xsl:apply-templates select=".//LimitDetails[./ParentLimitRefNo='']" />
</Limit>
</LimitDetails>
</xsl:copy>
</xsl:template>
<xsl:template match="LimitDetails">
<xsl:variable name="LimitRefNo" select="./LimitRefNo" />
<xsl:apply-templates select="@*|node()" />
<xsl:if test="../LimitDetails[./ParentLimitRefNo = $LimitRefNo]">
<SubLimit>
<xsl:apply-templates select="../LimitDetails[./ParentLimitRefNo = $LimitRefNo]" />
</SubLimit>
</xsl:if>
</xsl:template>
</xsl:transform>
当我打开与IE11的XML,只显示文本节点,它不显示为XML格式,请让我知道什么是错的这个。
浏览器是专门用来显示HTML,而不是一个XSL转换的XML结果。 –