将行与单个SQL Server中的另一行进行比较表

我有一个包含以下行数据的表。将行与单个SQL Server中的另一行进行比较表

EngID Tower Billing Amt 
100  ICS  Y  5000 
100  EDT  Y  7777 
100  ICS  N  2000

和我想要的结果设置为通过塔&主机ID和投入相应的列的数量被合并基于结算标准（发票金额或不开发票）。所以，下面是最终的结果集应该是什么样子的上表：

EngID Tower Inv Amt (Amt when Billing = Y) Non-Invoiced Amt (Billing=N) 
100  ICS  5000          2000 
100  EDT  7777

我能够得到的结果通过使用下面的查询中设置的第1行：

Select Temp1.Tower, Temp1. EngID, Temp2.InvoiceAmt as [Inv Amt], Temp1.InvoiceAmt AS [Non-Invoiced Amt] from 
(
SELECT EngID, TOWER,BILLING, InvoiceAmt,RANK() OVER (PARTITION BY EngID, TOWER ORDER BY BILLING) AS RNK 
    FROM [GDF].[dbo].[Sample] ) Temp1 INNER JOIN (SELECT EngID, TOWER,Billing,InvoiceAmt, RANK() OVER (PARTITION BY EngID, TOWER ORDER BY BILLING) AS RNK 
    FROM [GDF].[dbo].[Sample]) Temp2 ON 

    Temp1.EngID = Temp2.EngID 
    AND (Temp1.Tower = Temp2.Tower AND Temp1.Billing < Temp2.Billing)

然而，努力获得第二排结果。我的计划是通过两个单独的查询获得两行，然后进行联合以合并结果。

来源

2016-12-20 sqlrookuser

一种方法是有条件聚集：我们也可以不使用OUTER它

select s.engid, s.tower, 
     sum(case when s.billing = 'Y' then amt end) as billing_y, 
     sum(case when s.billing = 'N' then amt end) as billing_n 
from gdf.dbo.sample s 
group by s.engid, s.tower;

来源

2016-12-20 03:47:31

这是什么'gdf.dbo'是什么意思？ –

这是SQL Server中使用的三分命名约定。 –

试试这个：

select engid, tower, 
    sum(case when billing = 'Y' then amt end) Inv_amt, 
    sum(case when billing = 'N' then amt end) Non_Inv_amt, 
from my_table 
group by 
    engid, 
    tower;

来源

2016-12-20 03:46:32 GurV

适用如下：

select A.EngID, 
    sum(A.Amt) as [Inv Amt (Amt when Billing = Y)], 
    sum(B.Amt) as [Non-Invoiced Amt (Billing=N)] 
from #test A 
outer apply(select b.Amt from #test B where A.EngID = b.EngID and b.tower = a.tower and B.Billing = 'n') B 
where a.billing = 'y' 
group by A.EngID, A.Tower

简单LEFT JOIN：

select A.EngID, 
    sum(A.Amt) as [Inv Amt (Amt when Billing = Y)], 
    sum(B.Amt) as [Non-Invoiced Amt (Billing=N)] 
from #test A 
left join #test B on A.EngID = b.EngID 
    and b.tower = a.tower 
    and B.Billing = 'n' 
where a.billing = 'y' 
group by A.EngID, A.Tower

来源

2016-12-20 03:59:50 Susang

此代码将给出所需的结果没有任何复杂性。请从下面提到的查询找到输出的快照。希望我解决了您的问题。

WITH Mycte 
AS 
(
Select ENGID,Tower,Case When Billing='Y' Then ISNULL(SUM(Amt),0) END AS Inv_Amt, 
Case When Billing='N' Then ISNULL(SUM(Amt),0) END AS Non_Inv_Amt from #Sample 
group by ENGID,Tower,Billing 
) 
Select ENGID,Tower,SUM(Inv_Amt) AS Inv_Amt,SUM(Non_Inv_Amt) AS Non_Inv_Amt from mycte 
group by ENGID,Tower

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2016-12-20 06:23:06

将行与单个SQL Server中的另一行进行比较表

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