使用XML的VB.NET服务器协议违规“Section = ResponseStatusLine”

我试图发送一个XML片段到我的本地主机服务器。我已经能够成功连接和（我认为）成功发送片段。但是，当我运行我的程序时，我得到一个未处理的WebException。异常详细信息全文如下：使用XML的VB.NET服务器协议违规“Section = ResponseStatusLine”

System.Net.WebException was unhandled 
Message=The server committed a protocol violation. Section=ResponseStatusLine 
Source=System 
StackTrace: 
    at System.Net.HttpWebRequest.GetResponse() 
    at Automation_Algorithm.AutomationForm.cmdStart_Click(Object sender, EventArgs e) in C:\Users\ConzM\documents\visual studio 2010\Projects\Automation Algorithm\Automation Algorithm\AutomationForm.vb:line 29 
    at System.Windows.Forms.Control.OnClick(EventArgs e) 
    at System.Windows.Forms.Button.OnClick(EventArgs e) 
    at System.Windows.Forms.Button.OnMouseUp(MouseEventArgs mevent) 
    at System.Windows.Forms.Control.WmMouseUp(Message& m, MouseButtons button, Int32 clicks) 
    at System.Windows.Forms.Control.WndProc(Message& m) 
    at System.Windows.Forms.ButtonBase.WndProc(Message& m) 
    at System.Windows.Forms.Button.WndProc(Message& m) 
    at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m) 
    at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m) 
    at System.Windows.Forms.NativeWindow.DebuggableCallback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam) 
    at System.Windows.Forms.UnsafeNativeMethods.DispatchMessageW(MSG& msg) 
    at System.Windows.Forms.Application.ComponentManager.System.Windows.Forms.UnsafeNativeMethods.IMsoComponentManager.FPushMessageLoop(IntPtr dwComponentID, Int32 reason, Int32 pvLoopData) 
    at System.Windows.Forms.Application.ThreadContext.RunMessageLoopInner(Int32 reason, ApplicationContext context) 
    at System.Windows.Forms.Application.ThreadContext.RunMessageLoop(Int32 reason, ApplicationContext context) 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.OnRun() 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.DoApplicationModel() 
    at Microsoft.VisualBasic.ApplicationServices.WindowsFormsApplicationBase.Run(String[] commandLine) 
    at Automation_Algorithm.My.MyApplication.Main(String[] Args) in 17d14f5c-a337-4978-8281-53493378c1071.vb:line 81

我的代码（在第11场首发）：

Private Sub cmdStart_Click(sender As System.Object, e As System.EventArgs) Handles cmdStart.Click 
    Dim requestNF As WebRequest = WebRequest.Create("http://127.0.0.1:4096") 
    requestNF.Method = "POST" 
    Dim datastring As String 
    Dim getdata = 
     <?xml version='1.0' encoding='ISO-8859-1'?> 
     <MLCommandSet> 
      <info/> 
     </MLCommandSet>                  '/ 
    datastring = "<?xml version='1.0' encoding='ISO-8859-1'?>" & vbNewLine & getdata.ToString() 
    Dim byteArray As Byte() = Encoding.UTF8.GetBytes(datastring) 
    requestNF.ContentLength = byteArray.Length 
    requestNF.ContentType = "text/xml" 
    Dim dataStream As Stream = requestNF.GetRequestStream() 
    dataStream.Write(byteArray, 0, byteArray.Length) 
    txtXMLOutFF.AppendText(getdata.ToString & vbNewLine) 
    dataStream.Close() 

    Dim responseNF As Object = requestNF.GetResponse.GetResponseStream '<---breaks here' 
    Console.WriteLine(CType(responseNF, HttpWebResponse).StatusDescription.ToString) 
    txtXMLInFF.Text = CType(responseNF, HttpWebResponse).StatusDescription.ToString 
    dataStream = responseNF.GetResponseStream 
    Dim readerNF As New StreamReader(dataStream) 
    Dim responseFromServerNF As String = readerNF.ReadToEnd 
    Console.WriteLine(responseFromServerNF) 
    txtXMLInFF.AppendText(responseFromServerNF.ToString & vbNewLine) 
    readerNF.Close() 
    dataStream.Close() 
    responseNF.Close() 
End Sub

有人能提供一些线索这对我来说？

来源

2012-06-26 Matt

尽管我还没有达到与应用程序通信的预期目标，但我确实发现问题是通信是通过原始TCP/IP消息，而不是像我所假设的XML或HTTP请求。所以，我想出了一个解决疑难清单运行时，你得到的“服务器违反协议：条：ResponseStatusLine”错误：

下面的代码添加到您的app.config文件：（它允许不正确头部可以通过）

<system.net> 
    <settings> 
     <httpWebRequest useUnsafeHeaderParsing = "true"/> 
    </settings> 
</system.net>

如果在清理和重建后不起作用，那么您连接的服务器可能不会发送WebRequest数据。为了测试这个，我使用了一个Telnet客户端。
要使用Telnet测试数据，请下载并打开Telnet客户端（Windows，我建议PuTTYtel，Unix和其他人通常可以启动他们的终端/命令提示符并键入telnet来激活）。

a）输入您尝试连接的服务器和相应字段中的端口号（Windows）或在终端中键入telnet -o servername:portnumber，然后按Enter键。（Unix/Linux风格）

b）当窗口出现时，尝试输入原始查询，仔细记录任何空白或换行规范。在我的情况下，我键入：
```
<?xml version='1.0' encoding='ISO-8859-1'?> 
<MLCommandSet> 
    <info/> 
</MLCommandSet> 
```
并按下回车键。当我这样做时，我立即看到了我正在寻找的应用程序的输出。：D
但是，如果这不起作用，请在其他地方寻找解决方案，因为我可以帮您解决问题。

希望这有助于！

来源

2012-06-27 09:11:26 Matt

使用XML的VB.NET服务器协议违规“Section = ResponseStatusLine”

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