urlfetch无法在GAE中获取URL

此问题之前已被询问，但未找到可行的答案！urlfetch无法在GAE中获取URL

我在我的代码中使用urlfetch来获取url内容，但无法获取URL错误。继承人我的代码部分：

import cgi 
import webapp2 
from google.appengine.api import urlfetch 

class MainPage(webapp2.RequestHandler): 
    def get(self): 
     self.response.write(MAIN_PAGE_HTML) # MAIN_PAGE_HTML is defined .. 
class Hunt(webapp2.RequestHandler): 
    def flip(self): 
     page=urlfetch.fetch('http://103.4.253.46/search?q=nexus 4') 

#<////Rest Of the Code  /////>

我收到内部服务器错误，这

Traceback (most recent call last): 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 1535, in __call__ 
    rv = self.handle_exception(request, response, e) 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 1529, in __call__ 
    rv = self.router.dispatch(request, response) 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 1278, in default_dispatcher 
    return route.handler_adapter(request, response) 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 1102, in __call__ 
    return handler.dispatch() 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 572, in dispatch 
    return self.handle_exception(e, self.app.debug) 
    File "/base/data/home/runtimes/python27/python27_lib/versions/third_party/webapp2-2.5.2/webapp2.py", line 570, in dispatch 
    return method(*args, **kwargs) 
    File "/base/data/home/apps/s~dime-hunt/1.371847514565231627/hunt.py", line 61, in post 
    self.flip() 
    File "/base/data/home/apps/s~dime-hunt/1.371847514565231627/hunt.py", line 39, in flip 
    page=urlfetch.fetch('http://103.4.253.46/search?q=nexus 4') 
    File "/base/data/home/runtimes/python27/python27_lib/versions/1/google/appengine/api/urlfetch.py", line 270, in fetch 
    return rpc.get_result() 
    File "/base/data/home/runtimes/python27/python27_lib/versions/1/google/appengine/api/apiproxy_stub_map.py", line 612, in get_result 
    return self.__get_result_hook(self) 
    File "/base/data/home/runtimes/python27/python27_lib/versions/1/google/appengine/api/urlfetch.py", line 403, in _get_fetch_result 
    raise DownloadError("Unable to fetch URL: " + url + error_detail) 
DownloadError: Unable to fetch URL: http://103.4.253.46/search?q=nexus 4

我更换了网站名称与ip地址，但仍是同样的错误。我能够使用请求在本地在IDLE中进行测试时从站点获取数据。

来源

2013-11-24 rogue_leader

是它的建议，因为你有关系和4，而不是“％20”之间的空间？ – Back2Basics

@ Back2Basics奇怪，但它的工作！谢谢 –

'http://103.4.253.46/search?q=nexus%204'

通过更换20％的空间解决了这个错误由@ Back2Basics

来源

2013-11-24 10:59:15

urlfetch无法在GAE中获取URL

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