在SQL select中进行计算

Question

我想使用SELECT Query合并表中的值。 我的表格有5列：姓名，日期[最多三个日期（连续营业日）]和每天的三个值。

我想要一个输出：strName，SUM（Value1 + Value2 - Value3）from Date0，SUM（Value1 + Value2 - Value3）from Date1，SUM（Value1 + Value2 - Value3）from Date2。

输入：

strName myDate Value1 Value2 Value3 
X4 2012-06-14 26300 0 0 
X4 2012-06-15 0 4000 0 
X4 2012-06-18 0 5600 0 
X9 2012-06-14 764 0 0 
A3 2012-06-14 7850 0 0 
B 2012-06-14 5500 0 0 
C3 2012-06-14 269100 0 0 
D3 2012-06-14 395100 0 0 
D3 2012-06-15 0 0 500 

理想输出：

X4, 26300, 4000,5600 
X9, 760, 0, 0 
A3, 7850 
... 
D3, 395100, 0, -500 

我的表：

USE [MyTestBD] 
GO 
SET ANSI_NULLS ON 
GO 
SET QUOTED_IDENTIFIER ON 
GO 
SET ANSI_PADDING ON 
GO 
CREATE TABLE [dbo].[tbX](
[strName] [varchar](max) NOT NULL, 
[Value1] [float] NOT NULL, 
[myDate] [date] NOT NULL, 
[Value2] [float] NOT NULL, 
[Value3] [float] NOT NULL 
) ON [PRIMARY] 
GO 
SET ANSI_PADDING OFF 
GO 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'X4', 26300, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'X4', 0, CAST(0xCC350B00 AS Date), 4000, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'X4', 0, CAST(0xCF350B00 AS Date), 5600, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'X9', 764, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'A3', 7850, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'B', 5500, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'C3', 269100, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'D3', 395100, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'D3', 0, CAST(0xCC350B00 AS Date), 0, 500) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'D4', 400, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'D4', 0, CAST(0xCC350B00 AS Date), 400, 6600) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'E3', 361349, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'F6', 45500, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'F6', 0, CAST(0xCC350B00 AS Date), 11600, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'G4', 55979, CAST(0xCB350B00 AS Date), 0, 0) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'G4', 0, CAST(0xCC350B00 AS Date), 0, 19100) 
INSERT [dbo].[tbX] ([strName], [Value1], [myDate], [Value2], [Value3]) VALUES (N'G4', 0, CAST(0xCF350B00 AS Date), 0, 38300) 

PS：我没有发现我的问题一个很好的标题。随意编辑它。

Answer 1

试试这个：

SELECT 
    strName, 
    SUM(CASE rn WHEN 1 THEN Value1 + Value2 - Value3 END), 
    SUM(CASE rn WHEN 2 THEN Value1 + Value2 - Value3 END), 
    SUM(CASE rn WHEN 3 THEN Value1 + Value2 - Value3 END) 
FROM 
(
    SELECT *, ROW_NUMBER() OVER (PARTITION BY strName ORDER BY mydate) AS rn 
    FROM tbX 
) AS T1 

结果：

A3 7850  (null) (null) 
B 5500  (null) (null) 
C3 269100  (null) (null) 
D3 395100  -500 (null) 
D4 400   -6200 (null) 
E3 361349  (null) (null) 
F6 45500  11600 (null) 
G4 55979  -19100 -38300 
X4 26300  4000 5600 
X9 764   (null) (null) 

sqlfiddle

Answer 2

您的数据并不完全与你的解释一致，所以我会用你的解释而不是去。

我还会假设SQL Server 2005或更高版本。

WITH 
    sequenced_data 
AS 
(
    SELECT 
    ROW_NUMBER() OVER (PARTITION BY strName ORDER BY MyDate) AS sequence_id, 
    * 
    FROM 
    tbX 
) 
SELECT 
    strName, 
    SUM(CASE WHEN sequence_id = 1 THEN value1 + value2 - value3 ELSE 0 END) AS v1, 
    SUM(CASE WHEN sequence_id = 2 THEN value1 + value2 - value3 ELSE 0 END) AS v2, 
    SUM(CASE WHEN sequence_id = 3 THEN value1 + value2 - value3 ELSE 0 END) AS v3 
FROM 
    sequenced_data 
GROUP BY 
    strName 

Answer 3

在您的测试数据中，您有3个日期，因此您可以编写2个案例。 如果您打算增加各种最新的这个充满活力的支点可能是有用的

declare @col varchar(1000) 
declare @sql varchar(2000) 

select @col = COALESCE(@col + ', ','') + QUOTENAME(myDate) from (select distinct myDate from tbX) t 

select @col 

set @sql = 'select strName, ' + @col + ' 
from (SELECT [strName],myDate,sum(Value1+Value2-Value3) as suma FROM tbX group by [strName],myDate)p 
PIVOT(sum(suma) FOR myDate IN (' + @col + ') 
) AS pvt' 

print @sql 

exec (@sql)