JavaScript/jQuery：比较2个jSON对象并将结果输出到新对象

Question

我有一个api调用，它使用更新的jSON对象进行回复，我也有1个静态json对象文件。我正试图比较每个团队中具有相同名称的对象中的值。

因此，如果团队约翰在旧文件中有22个，并且现在有28个，那么新对象应该将Team John输出为6.减去2并显示差异。

我做了一个jsFiddle来帮助理解和更新。

最新更新：答案已被mscdeveloper解决！检查他的帖子并在下面回答。

UPDATE（未回答）：我已经找到了解决方案，同时在计算器搜索，这不正是我想要的，但我在这个过程中失去了球队的名字，我怎么能修复代码到它doesn不会删除它，我知道它与我有的groupByTypeID函数有关系吗？

更新的jsfiddle：https://jsfiddle.net/kqmfsz9n/5/

var obj1 = { 
    "teams": [ 
    { 
     name: 'Test 1', 
     numMembers: '50' 
    }, 
    { 
     name: 'Test 2', 
     numMembers: '12' 
    } 
    ] 
}; 

var obj2 = { 
    "teams": [ 
    { 
     name: 'Test 1', 
     numMembers: '75' 
    }, 
    { 
     name: 'Test 2', 
     numMembers: '18' 
    } 
    ] 
}; 

var newObj = {}; 
function groupByTypeID(arr) { 
    var groupBy = {}; 
    jQuery.each(arr, function() { 
    groupBy[this.name] = parseInt(this.numMembers); 
    }); 
    return groupBy; 
} 

var userArrayGroups = groupByTypeID(obj2.teams); 
var origArrayGroups = groupByTypeID(obj1.teams); 

var newObj = []; 
for (var prop in userArrayGroups) { 
    newObj[prop] = userArrayGroups[prop] - origArrayGroups[prop]; 
    newObj.push(userArrayGroups[prop] - origArrayGroups[prop]); 
    if (newObj[prop] == 0) { 
    delete newObj[prop]; 
    } 
} 

console.log(newObj); 

所有帮助表示赞赏！ 谢谢。

Answer 1

var obj1 = { 
     "teams": [ 
     { 
      name: 'Test 1', 
      numMembers: '50' 
     }, 
     { 
      name: 'Test 2', 
      numMembers: '12' 
     } 
     ] 
    }; 

    var obj2 = { 
     "teams": [ 
     { 
      name: 'Test 1', 
      numMembers: '75' 
     }, 
     { 
      name: 'Test 2', 
      numMembers: '18' 
     } 
     ] 
    }; 

    var newObj = {}; 
var items_arr=[]; //array of obj2 not exist in obj1 

    if(obj1.teams){    //if exist array of teams obj1 
    var o1teams = obj1.teams; 
    if(obj2.teams){  //if exist array of teams obj2 
     var o2teams = obj2.teams; 
     for(var key2 in o2teams){ 
      var o2teams = obj2.teams; 
      for(var key1 in o1teams){ 
        if(o2teams[key2].name==o1teams[key1].name){ 
         var numMembers_o1_int=parseInt(o1teams[key1].numMembers)||0; 
         var numMembers_o2_int=parseInt(o2teams[key2].numMembers)||0; 
         var result_numMembers_int=numMembers_o2_int-numMembers_o1_int; 
         var result_numMembers=result_numMembers_int+''; //convert to string 
         var items_for_add=o1teams[key1]; 
         items_for_add.numMembers=result_numMembers; 
         items_arr.push(items_for_add); 
        } 
      } 
     } 
     } 
    } 
    newObj.items=items_arr; 

    console.log(newObj); 

https://jsfiddle.net/mscdeveloper/uxv1t2a7/3/