Javascript - 谷歌地图，简单的反向地理编码 - 总是为零结果

Question

我有一个简单的谷歌地图拖动事件和地址查找。 在拖动事件上，我想更新纬度/经度输入字段（工作），但也要更新地址（不工作），。

我可能是太累了，而且很可能只是缺少一些微小的明显啄这里，但我似乎无法得到它的工作（总是返回零次的结果）..

见行动：http://jsfiddle.net/obmerk99/Ss4tp/

JS代码：

// <![CDATA[ 
var map; 
var markersArray = []; // to be used later to clear overlay array 
var marker; 
var address; 


jQuery(document).ready(function() { 
    var lat = parseFloat(jQuery('#LatTxt').val()); 
    var lon = parseFloat(jQuery('#LonTxt').val()); 

    var myLatlng = new google.maps.LatLng(lat, lon); 
    var myOptions = { 
     zoom: 4, 
     center: myLatlng, 
     mapTypeId: google.maps.MapTypeId.ROADMAP 
    }; 
    map = new google.maps.Map(jQuery('[id^=k99_geolocation_]')[0], myOptions); 
    placeMarker(myLatlng); 

    google.maps.event.addListener(map, 'click', function(event) { 
     placeMarker(event.latLng); 
    }); 

    // Find Adress and set zoom when found 

    jQuery('#k99_geo_address').click(function() { codeAddress() }); 
    function codeAddress() { 
     geocoder = new google.maps.Geocoder(); 
     var address = document.getElementById("address").value; 
     geocoder.geocode({ 'address': address}, function(results, status) { 
       if (status == google.maps.GeocoderStatus.OK) { 
       map.setCenter(results[0].geometry.location); 
        map.setZoom(11); // how to do that according to the level ?? (country ,city, street, house ??) 

       if (marker) { 
        marker.setPosition(results[0].geometry.location); 
       } 
       } else { 
       alert("Geocode was not successful for the following reason: " + status); 
       } 
      } 
    ); 
} 

    //Function to extract longitude 



    function placeMarker(location) { 
     if (marker) { 
      marker.setPosition(location); 
     } else { 
      marker = new google.maps.Marker({ 
       position: location, 
       draggable: true, 
       title: 'Drag me', 
       map: map 
      }); 
      markersArray.push(marker); // to be used later to clear overlay array 
     } 
    } 
// adding drag event 
google.maps.event.addListener(marker, 'dragend', function(event) { updatelonlat(); }); 

    // Removes the overlays from the map, but keeps them in the array 

    function clearOverlays() { 
     if (markersArray) { 
      for (var i = 0, length = markersArray.length; i < length; i++) { 
       markersArray[i].setMap(null); 
      } 
     } 
    } 
    //Jquery update HTML input boxes 

    function updatelonlat() { 
     jQuery('#LatTxt').val(marker.getPosition().lat()); 
     jQuery('#LonTxt').val(marker.getPosition().lng()); 
     geocoder = new google.maps.Geocoder(); 
     geocoder.geocode({ 'address': address}, function(results, status) { 
       if (status == google.maps.GeocoderStatus.OK) { 

      jQuery('#address').val(results[1].formatted_address); 

       } else { 
       alert("Geocode was not successful for the following reason: " + status); 
       } 
      }); 
    } 


    // add event click 
    google.maps.event.addListener(map, 'click', function(event) { 
     placeMarker(event.latLng); 
     //document.getElementById("#LatTxt").value = event.latLng.lat(); 
     //down lan lon values from http://tech.cibul.net/geocode-with-google-maps-api-v3/ 
     updatelonlat(); 
    }); 

}); 
    // ]]> 

Answer 1

在updatelonlat必须使用{latLng:marker.getPosition()}作为论据geocoder.geocode()