我正在写一个小应用程序(比“HelloWorld”稍大一些)。任务是创建一个生产者和几个消费者。生产者生成integeres并将它们放入动态堆栈(这是我的监视器对象),并且消费者试图从堆栈中获取这些整数。 我知道如何使用一个标志创建1个生产者+ 1个消费者,并在里面等待()。但是如何对多个消费者也这样做。使用java线程的多监视器同步
请看看我的代码:
public interface StackQueueIF {
void push(int value);
int pop();
}
public class DynamicStack implements StackQueueIF{
private volatile int stck[];
private volatile int tos;
boolean valueSet = false;
public DynamicStack(int size) {
stck = new int[size];
tos = -1;
}
@Override
public synchronized void push(int item) {
while(valueSet){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
if (tos == stck.length-1) {
System.out.println("---------STACK HAS BEEN DOUBLED--------");
int temp[] = new int[stck.length * 2];
for (int i = 0; i < stck.length; i++) temp[i] = stck[i];
stck = temp;
stck[++tos] = item;
}else
stck[++tos] = item;
valueSet = true;
notifyAll();
}
@Override
public synchronized int pop() {
while(!valueSet){
try {
wait();
} catch (InterruptedException e) {
e.printStackTrace();
}
}
valueSet = false;
notifyAll();
return stck[tos--];
}
}
class Producer implements Runnable{
StackQueueIF queue;
String producerName;
private static int counter = 0;
public Producer(StackQueueIF queue, String name) {
this.queue = queue;
this.producerName = name;
new Thread(this,producerName).start();
}
@Override
public void run() {
while(true){
System.out.println(this.producerName + " puts " + (++counter)
+ " into stack");
this.queue.push(counter);
try {
Thread.sleep(500);
} catch (InterruptedException e) {
System.err.println(producerName + " interrupted");
e.printStackTrace();
}
}
}
}
class Consumer implements Runnable{
StackQueueIF queue;
String consumerName;
public Consumer(StackQueueIF queue, String consumerName) {
this.queue = queue;
this.consumerName = consumerName;
new Thread(this, this.consumerName).start();
}
@Override
public void run() {
while(true){
System.out.println(this.consumerName + " gets " + queue.pop() + " from stack");
try {
Thread.sleep(500);
} catch (InterruptedException e) {
System.err.println(consumerName + "interrupted");
e.printStackTrace();
}
}
}
}
public class QueueTester {
public static void main(String[] args) {
StackQueueIF queue = new DynamicStack(10);
new Producer(queue,"Producer №1");
new Consumer(queue,"Consumer №1");
new Consumer(queue,"Consumer №2");
}
}
如果你运行这段代码,你会看到只有消费者#1变值而消费者#2一无所获。那就是问题所在。他们都应该有机会从堆叠中获得某些东西,或者等待它是空的。 –
+1对于使用№;) –