SQL从表中获得第一个不同的值

Question

我想检查此SQL是否正确。

"SELECT TOP 1 * FROM (SELECT DISTINCT [Entry Date] FROM [" + group + "]) WHERE [Entry Date]>#" + initDate + "# ORDER BY [Entry Date]"

预先感谢您

解决：我发现SQL完美的作品。这只是我在我的程序中犯了一个小错误。现在解决了。

Answer 1

你想要这个吗？

select min([Entry Date]) 
from [group] 
where [Entry Date] > #" + initDate 

或本：

select top 1 * 
from [group] 
where [Entry Date] > #" + initDate 
order by [Entry Date] 

Answer 2

这应该工作。

SELECT B.* FROM (
SELECT [EntryDate] FROM Group 

EXCEPT 

SELECT [EntryDate] FROM (

SELECT [EntryDate] 
,ROW_NUMBER() OVER (ORDER BY [EntryDate]) AS Rown 
from Group 
         )A WHERE Rown > 1)B JOIN Group C ON a.[EntryDate] = B.[EntryDate] 

WHERE [Entry Date] > #" + initDate 
ORDER BY [Entry Date]