2016-05-12 72 views
1

我正在尝试使用r和ggplot2创建堆积面积图。我想看看 like this,而不是areas overlap and have holes。我试图确保这些区域被堆积起来,以使最近月份(本例中为2016-05)的价值最大的区域位于底部。使用R和ggplot2的堆积面积图有孔

相关帖子like this one似乎有数据漏洞,这似乎不是问题在这里。

这里的示例代码来重现问题:

sample.data <- structure(
    list(
    rank = structure(
     c(34L, 34L, 34L, 35L, 35L, 35L, 34L, 34L, 34L, 34L, 35L, 35L, 35L, 35L, 35L, 34L), 
     .Label = c("1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31", "32", "33", "34", "35"), 
     class = "factor"), 
    vendor = structure(
     c(1L, 1L, 1L, 2L, 2L, 2L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 1L), 
     .Label = c("34", "35"), 
     class = "factor"), 
    year.month = c("2015-12", "2016-01", "2015-11", "2015-12", "2016-01", "2015-10", "2016-03", "2016-02", "2015-10", "2016-04", "2015-11", "2016-05", "2016-04", "2016-03", "2016-02", "2016-05"), 
    value = c(431616L, 272224L, 229288L, 195284L, 155168L, 154194L, 149784L, 137302L, 126612L, 117408L, 94141L, 56161L, 54606L, 53173L, 49898L, 45348L)), 
    .Names = c("rank", "vendor", "year.month", "value"), 
    row.names = c(6L, 8L, 4L, 5L, 7L, 1L, 12L, 10L, 2L, 14L, 3L, 15L, 13L, 11L, 9L, 16L), 
    class = "data.frame" 
) 

ggplot(data = sample.data, aes(x = year.month, y = value, group = vendor, color = vendor, reorder(-value), fill=vendor)) + 
    geom_area() 

在此先感谢您的帮助。

回答

0

尝试:+ geom_area(位置= “躲闪”,STAT = “身份”)

0

以下工作:

ggplot(data = sample.data[order(sample.data$vendor),], 
     aes(x = year.month, y = value, group = vendor, color = vendor, 
      reorder(-value), fill=vendor)) + geom_area() 

您刚刚订购您的数据:sample.data[order(sample.data$vendor),]

如果你想改变图形的顺序,你要“relevel”被存储为一个因素厂商变量:

sample.data$vendor <- relevel(sample.data$vendor, ref="35") 

下面是一些代码,以找出供应商设置基准水平根据您的标准:

with(sample.data, sample.data[year.month=="2016-05", 
         "vendor"][which.max(sample.data[year.month=="2016-05", "value"])]) 
+0

感谢您的快速响应!我认为这非常接近,但我试图确保这些区域是堆叠的,以便在最近一个月(本例中为2016-05)具有最大价值的区域位于底部。我尝试用几个地方的“供应商”代替“价值”,但似乎并不奏效。 – Matt

+0

由于您的供应商变量是一个因素,因此您需要使用''repvel'来实现此目的。看到我上面的代码。 – lmo