如何在Android中创建一个httppost请求？

Question

我知道这应该是很容易在网上找到，但没有文章解决了我的问题，所以我来这么一段help.I想使android系统的httppost请求一个WCF RESTful Web服务。我想创建一个xml然后我想将其发布到该服务并获得该服务的响应。

我创建了一个WCF REST服务，它有接受XML和应对back.Here是该方法的代码的方法：

[OperationContract] 
      [WebInvoke(Method = "POST", 
        RequestFormat = WebMessageFormat.Xml, 
        ResponseFormat = WebMessageFormat.Xml, 
        UriTemplate = "DoWork1/{xml}", 
        BodyStyle = WebMessageBodyStyle.Wrapped)] 
      XElement DoWork1(string xml); 

    public XElement DoWork1(string xml) 
      { 
       StreamReader reader = null; 
       XDocument xDocRequest = null; 
       string strXmlRequest = string.Empty; 
       reader = new StreamReader(xml); 
       strXmlRequest = reader.ReadToEnd(); 
       xDocRequest = XDocument.Parse(strXmlRequest); 
       string response = "<Result>OK</Result>"; 
       return XElement.Parse(response); 
     } 

下面是Android的代码发布XML：

String myXML = "<? xml version=1.0> <Request> <Elemtnt> <data id=\"1\">E1203</data> <data id=\"2\">E1204</data> </Element> </Request>"; 
       HttpClient httpClient = new DefaultHttpClient(); 
             // replace with your url 
       HttpPost httpPost = new HttpPost("http://192.168.0.15/Httppost/Service1.svc/DoWork1/"+myXML); 

此代码会在路径异常中抛出非法字符。

我怎样才能使发布的XML文件从Android这项服务。任何建议将非常感激。

Answer 1

public class HTTPPostActivity extends Activity { 

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.main); 

    makePostRequest(); 

} 
private void makePostRequest() { 


    HttpClient httpClient = new DefaultHttpClient(); 
          // replace with your url 
    HttpPost httpPost = new HttpPost("www.example.com"); 


    //Post Data 
    List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2); 
    nameValuePair.add(new BasicNameValuePair("username", "test_user")); 
    nameValuePair.add(new BasicNameValuePair("password", "123456789")); 


    //Encoding POST data 
    try { 
     httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair)); 
    } catch (UnsupportedEncodingException e) { 
     // log exception 
     e.printStackTrace(); 
    } 

    //making POST request. 
    try { 
     HttpResponse response = httpClient.execute(httpPost); 
     // write response to log 
     Log.d("Http Post Response:", response.toString()); 
    } catch (ClientProtocolException e) { 
     // Log exception 
     e.printStackTrace(); 
    } catch (IOException e) { 
     // Log exception 
     e.printStackTrace(); 
    } 

} 

} 

Answer 2

要连接到Android上的WCF服务，您必须使用外部库如ksoap。 enter link description here

然后你就可以适应您的需求这个类：只有在应用context.Pass数据到活动

SoapWorker.SoapRequest request = new SoapWorker.SoapRequest(URL,METHOD_NAME,NAMESPACE); 
    request.addParam(KEY,VALUE); 
    .... 
    request.addParam(KEY,VALUE); 

    SoapWorker worker = new SoapWorker(){ 

     @Override 
     public Object parseResponse(Object response) { 
      if(response==null) 
       return null; 
      //parse response 
      // this is background thread 
      return response; 
     } 

     @Override 
     protected void onPostExecute(Object o) { 
      super.onPostExecute(o); 
      // this is ui thread 
      //update your ui 
     } 
    }; 
    worker.execute(request); 

使用此asynck任务：

public abstract class SoapWorker extends AsyncTask<SoapWorker.SoapRequest,Void,Object> { 

public static class SoapRequest{ 

    private LinkedHashMap<String,Object> params; 
    private String methodName; 
    private String namespace; 
    private String actionName; 
    private String url; 
    public SoapRequest(String url, String methodName,String namespace){ 
     this.methodName = methodName; 
     this.params = new LinkedHashMap<>(); 
     this.namespace=namespace; 
     this.actionName=this.namespace + "IService/" + methodName; 
     this.url=url; 
    } 
    public void addParam(String key,Object value){ 
     this.params.put(key,value); 
    } 
} 

@Override 
protected Object doInBackground(SoapRequest input) { 

    try { 
     SoapObject request = new SoapObject(input.namespace, input.methodName); 
     for(Map.Entry<String, Object> entry : input.params.entrySet()){ 
      request.addProperty(entry.getKey(),entry.getValue()); 
     } 
     SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); 
     envelope.dotNet = true; 
     envelope.setOutputSoapObject(request); 
     HttpTransportSE androidHttpTransport = new HttpTransportSE(input.url); 
     androidHttpTransport.call(input.actionName, envelope); 
     input.params.clear(); 

     return parseResponse(envelope.getResponse()); 
    } catch (Exception e) { 
     Log.e("SoapWorker", "error " + e); 
     return e; 
    } 

} 

@WorkerThread 
public abstract Object parseResponse(Object response); 


} 

使用这个类像/片段仅使用来自绿色roboot或otto的EventBus。