MySQL的选择1000增量数

Question

是否有可能选择增加的数字，如：

num 
1000 
1001 
1002 
1003 
1004 
... 
1999 

我已经试过：

set @i=999; 
select @i:=@i+1 as num 
limit 1000 

也：

set @i=999; 
select @i:=@i+1 as num 
where @i <1999; 

Answer 1

你必须在一个有1000行的表操作，以获得想要的东西：

SELECT @i := @i+1 AS num 
FROM (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS t 
CROSS JOIN (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS s 
CROSS JOIN (
    SELECT 1 AS x UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 AS x UNION ALL 
    SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 
) AS u 
CROSS JOIN (SELECT @i := 999) AS var 

在10使用CROSS JOIN 10 10表组合，我们得到一个1000行线表。以此为基础，我们可以计算所需的@i值的顺序。

Demo here

Answer 2

我假设（可能是错误的）你试图根据自动递增的主键选择行，看到这是MySQL？

“BETWEEN”关键字会更好用，而不是使用变量吗？

例如，如果你想选择表“mytable的”和“民”行是主键：

SELECT num FROM myTable 
WHERE num BETWEEN 999 AND 1999 

Answer 3

下面是一个简单的查询，打印数量1000 - 1999与一组增量值。

DECLARE @firstNumber INT 
DECLARE @lastNumber INT 
DECLARE @incrementBy INT 

SET @firstNumber = 1000 
SET @lastNumber = 1999 
SET @incrementBy = 1 

CREATE TABLE #TEMP (number INT) 

WHILE(@firstNumber <= @lastNumber) 
BEGIN 
    INSERT INTO #TEMP VALUES (@firstNumber) 
    SET @firstNumber = @firstNumber + @incrementBy 
END 

SELECT * FROM #TEMP 

DROP TABLE #TEMP