嗨,大家好我有问题parseInt行为像字符串行为。 更可能是愚蠢的我做错了。 问题是代码JavaScript,添加2个变量,我已经使用parseInt在一起输出像一个字符串
function getNewDate()
{
var dateEntered = document.getElementById('Temp').value; //input got from a form
var daysEntered = document.getElementById('Temp1').value ; //input got from a form
var month = dateEntered.charAt(5)+dateEntered.charAt(6); //creating month
var date = dateEntered.charAt(8)+dateEntered.charAt(9); //date
var year = dateEntered.charAt(0)+dateEntered.charAt(1)+dateEntered.charAt(2)+dateEntered.charAt(3); //and year from input
var newDate = 0 ;
parseInt(month) ; //making the below variables integers for calculations
parseInt(daysEntered) ;
parseInt(date) ;
parseInt(newDate) ;
var newFullDate = "" ;
if(month == 01)
{
newDate = date + daysEntered ; //if i enter 01/01/2016 as the date
if(newDate > 31) //and 5 for days entered
{ //when i piece together the newFullDate
month = 02 ; //it outputs like 2016-01-015
date = 0 ;
daysEntered = newDate - 31 ;
}
else
{
newFullDate = ""+year +"-"+"01"+"-"+newDate ;
document.getElementsByName('output')[0].value= newFullDate;
}
}
您需要在指定'parseInt函数(月)'等,以一个变量 在'VAR month = parseInt(dateEntered.charAt(5)+ dateEntered.charAt(6));' – estherz
在'parseInt(month)'行放置一个断点。执行后,检查'month'的值,你会看到它没有改变。这应该给你一个很好的线索。 –