这回0有关的问题:SCTP with Multihoming as a Drop In Replacement for TCP选择在一个封闭的SCTP套接字
我有一个使用TCP运行完全正常的一个简单的回声客户机/服务器的并发应用程序。我可以将一个文件传输到客户端上的stdin,客户端将接收到所有数据,请拨select
返回1,表示套接字可读,然后读取的呼叫将返回0,指示EOF/FIN。客户端然后将退出。一切都很好。
但是,SCTP上的相同应用程序会导致问题。唯一的改变是从IPPROTO_TCP到IPPROTO_SCTP。服务器分叉,echo回数据,孩子退出并由父母收回。客户端收到所有的数据,但之后select
一直返回0个描述符(没有超时我添加它将永远挂起)。
世界正在发生什么?
下面是客户端的代码如下所示:
#!/usr/bin/perl -w
use strict;
use Socket;
# forward declaration
sub logmsg;
my $remote = shift || "localhost";
my $port = 9877;
($port) = $port =~ /^(\d+)$/ or die "invalid port";
my $iaddr = inet_aton($remote) || die "no host: $remote";
my $paddr = sockaddr_in($port, $iaddr);
my $proto = getprotobyname('sctp');
my $sockfd;
socket($sockfd, PF_INET, SOCK_STREAM, $proto) || die "socket: $!";
connect($sockfd, $paddr) || die "connect: $!";
str_cli($sockfd);
exit(0);
#----- subs down here ------#
sub str_cli {
my $sockfd = shift;
my ($n, $buff, $stdineof, $s);
my $rin = '';
$stdineof = 0;
while (1) {
if ($stdineof == 0) {
vec($rin, fileno(STDIN), 1) = 1;
}
vec($rin, fileno($sockfd), 1) = 1;
my $nfound = select($rin, undef, undef, 1.0);
if ($nfound < 0) {
next if $!{EINTR};
die "select: $!";
} else { print "\$nfound == $nfound\n"; }
if (vec($rin, fileno($sockfd), 1) == 1) { # socket readable
print "trying to read from sockfd\n";
$n = sysread($sockfd, $buff, 1024);
if (!defined($n) || $n < 0) {
# resume if sysread() returned because a signal was received
next if $!{EINTR};
die "sysread: $!";
} elsif($n == 0) {
if ($stdineof == 1) { return; } # normal termination
else { die "str_cli: server terminated prematurely"; }
}
writen(*STDOUT, $buff);
}
if (vec($rin, fileno(STDIN), 1) == 1) { # stdin readable
$n = sysread(STDIN, $buff, 1024);
if (!defined($n) || $n < 0) {
# resume if sysread() returned because a signal was received
next if $!{EINTR};
die "sysread: $!";
} elsif($n == 0) {
$stdineof = 1;
if (!defined($s = shutdown($sockfd, SHUT_WR))
|| $s == 0) { die("shutdown: $!"); }
vec($rin, fileno(STDIN), 1) = 0;
next;
}
writen($sockfd, $buff);
}
}
}
sub writen {
my ($connfd, $buff) = @_;
my $nleft = length($buff);
my $total = 0;
my $nwritten = 0;
while ($nleft) {
if (($nwritten = syswrite($connfd, $buff, $nleft, $total)) <= 0) {
# resume if syswrite() returned because a signal was received
# 0 indicates an error in this context
next if $!{EINTR};
die "syswrite: $!";
}
$nleft -= $nwritten;
$total += $nwritten;
}
}
sub logmsg { print "$0 $$: @_ at ", scalar localtime, "\n" }
请记住,这完美的作品通过TCP。我在Ubuntu 9.04上安装了所有需要的sctp软件包。
那么在SCTP中有没有一种方法可以告诉套接字关闭,而不是应用程序协议级别通知? – 2010-02-13 22:12:30
如果您想发送一个指示,表示您已完成发送,但仍希望保持连接以接收响应,并且不想在应用程序层执行此操作,则可以将数据发送到单独的SCTP流中。接收器可以对该流的关闭作出反应,并在不同的流中发回响应。 – mark4o 2010-02-13 22:43:05
@ mark4o:您需要使用sctp特定API调用来做到这一点,对吗?有没有使用标准套接字API的方法?只是好奇在移植一个你不想引入sctp特定api调用的现有TCP应用程序时可以做些什么。 – 2010-02-14 08:23:58