误差在与不迭代对象

Question

Python类我有一个下面的错误消息

Traceback (most recent call last): 
    File "C:\Python27\lib\site-packages\IPython\core\interactiveshell.py", line 2721, in run_code 
    exec code_obj in self.user_global_ns, self.user_ns 
    File "<ipython-input-257-84ae6ec7b6f6>", line 1, in <module> 
    accuracy.ra_os 
    File "<ipython-input-255-a91d95432efe>", line 32, in ra_os 
    return np.average([(ref.intersection(s).area/s.area) for s in seg]) 
TypeError: 'Polygon' object is not iterable 

其中多边形是shapely的Polygon class。

我有自己的类精度： accuracy.ra_os

Traceback (most recent call last): 
    File "C:\Python27\lib\site-packages\IPython\core\interactiveshell.py", line 2721, in run_code 
    exec code_obj in self.user_global_ns, self.user_ns 
    File "<ipython-input-45-84ae6ec7b6f6>", line 1, in <module> 
    accuracy.ra_os 
    File "<ipython-input-7-1e04291926b0>", line 35, in ra_os 
    return np.average([(ref.intersection(s).area/s.area) for s in seg]) 
TypeError: 'Polygon' object is not iterable 

参考（一个）和分段（一个或多个）的多边形

ref = <shapely.geometry.polygon.Polygon at 0x4997b38> 
seg = [<shapely.geometry.polygon.Polygon at 0x4b972e8>, <shapely.geometry.polygon.Polygon at 0x49c7390>] 



import math 
import numpy as np 
from shapely.geometry import Polygon 
nan = np.nan 



class Accuracy(object): 
    def __init__(self, ref, seg=None): 
     self.ref = ref 
     self.seg = seg 

    @property 
    def area(self): 
     return self.ref.area 

    @property 
    def perimeter(self): 
     return self.ref.length 

    @property 
    def centroidX(self): 
     return self.ref.centroid.x 

    @property 
    def centroidY(self): 
     return self.ref.centroid.y 

    @property 
    def segments(self): 
     if self.seg: 
      return len(self.seg) 
     else: 
      return 0 

    @property 
    def ra_or(self): 
     if self.seg: 
      return np.average([(ref.intersection(s).area/ref.area) for s in seg]) 
     else: 
      return nan 

    @property 
    def ra_os(self): 
     if self.seg: 
      return np.average([(ref.intersection(s).area/s.area) for s in seg]) 
     else: 
      return nan 

精度=精度（REF，seg_overlap）之间的统计值

如果我在班级以外运行功能我没有这个错误

np.average([(ref.intersection(s).area/ref.area) for s in seg_overlap]) 
Out[47]: 0.48709794373000681 

Answer 1

你的意思是说self.seg，而不是仅仅seg：

return np.average([(ref.intersection(s).area/ref.area) for s in self.seg]) 
                   ^^^^^ 

（在这两个函数）

我觉得你不小心指具有相同名称的全局对象。