了解pythons int方法

Question

我有一个字符串，"stringify"。这样做的：

int("stringify",36) 

回报：

81323539083358 

有没有一种办法，这个数字转换回 “字符串”？

Answer 1

没有这个数字编码回基地36内置的方式，但对维基百科的一个Python实现：
http://en.wikipedia.org/wiki/Base_36#Python_implementation

这里是代码稍加修改的版本（只是改变了大写字母为小写）：

def base36encode(number, alphabet='abcdefghijklmnopqrstuvwxyz'): 
    """Converts an integer to a base36 string.""" 
    if not isinstance(number, (int, long)): 
     raise TypeError('number must be an integer') 

    base36 = '' 
    sign = '' 

    if number < 0: 
     sign = '-' 
     number = -number 

    if 0 <= number < len(alphabet): 
     return sign + alphabet[number] 

    while number != 0: 
     number, i = divmod(number, len(alphabet)) 
     base36 = alphabet[i] + base36 

    return sign + base36 

>>> base36encode(81323539083358) 
'stringify' 

Answer 2

只是为了好玩在这里是作为一个编解码器

import codecs 
class SimpleB36Encoder: 
    def encode(self,txt,errors=[]): 
     return str(int(txt,36)),1 

    def decode(self,txt,errors=[]): 
     number = int(txt) 
     alphabet = "abcdefghijklmnopqrstuvwxyz" 
     base36 = '' 
     sign = '' 
     if number < 0: 
      sign = '-' 
      number = -number 
     if 0 <= number < len(alphabet): 
      return sign + alphabet[number] 
     while number != 0: 
      number, i = divmod(number, len(alphabet)) 
      base36 = alphabet[i] + base36 
     return sign + base36,1 


def find_b36(search=""): 
    if search.lower() in ["base36","b36","36"]: 
     return codecs.CodecInfo(
      name='base36', 
      encode=SimpleB36Encoder().encode, 
      decode=SimpleB36Encoder().decode 
      ) 

codecs.register(find_b36) 
encoded = "stringify".encode("36") #note this is a string 
print "stringify encodes to %s"%encoded 
decoded = encoded.decode("36") 
print "%s decodes to %s"%(encoded,decoded)