我遇到问题从我的数据库使用where子句与for循环变量检索数据。此代码当前可以从数据库中检索数据,但是从数据库中检索到的值存储。在for循环中的数字1仍然很好。但是当它进入下一个。收集的数据是1和2的组合。当它最终到达循环结尾时,显示所有数据。 哪个代码的一部分,必须进行编辑,以数据的显示改变到非累积PHP SQL其中声明与循环变量
<?php
$sectorcount = $row_SectorCount['COUNT(*)'];
//number of rows in database
$spendingname= array();
$spendingpercent= array();
$spendingid= array();
?>
// Add some data to the details pie chart
options_detail_1.series.push({ name: 'Tax Spending Detail', data: [] });
$(document).ready(function() {
chart_main = new Highcharts.Chart(options_main);
chart_detail_1 = new Highcharts.Chart(options_detail_1);
})
function push_pie_detail(sectorid) {
switch(sectorid)
{
<?php
for ($i=1; $i<=$sectorcount; $i++)
{
echo "case 'sector".$i."':" ,
"setTimeout", "(" , '"chart_detail_1.series[0].remove(false)", 1000);' ,
"chart_detail_1.addSeries(options_detail_1, false);" ,
"chart_detail_1.series[1].setData([";
mysql_select_db($database_conn2, $conn2);
$query_Spending = "SELECT CONCAT(spending.SectorID, spending.ExpenditureID) AS 'SpendingID',
expenditure.ExpenditureName, spending.SpendingPercent, spending.SectorID
FROM spending
INNER JOIN expenditure ON spending.ExpenditureID = expenditure.ExpenditureID
WHERE spending.SectorID = '.$i.'";
$Spending = mysql_query($query_Spending, $conn2) or die(mysql_error());
$totalRows_Spending = mysql_num_rows($Spending);
while($row_Spending = mysql_fetch_assoc($Spending))
{
$spendingname[] = $row_Spending['ExpenditureName'];
$spendingpercent[] = $row_Spending['SpendingPercent'];
$spendingid[]= $row_Spending['SpendingID'];
}
mysql_free_result($Spending);
$a = 0;
foreach ($spendingid as $sgi => $sgid)
{
if ($a > 0) echo ', '; // add the comma
echo "{
name: '$spendingname[$sgi]',
y: ". $spendingpercent[$sgi] * $tax .",
id: ' $sgid',
}";
$a++;
}
echo "], false);" ,
"chart_detail_1.redraw();",
"break;";
}
?>
default:
break;
}
}
你如何设法解决它?即时通讯真的很新的PHP请指导我:D – 2012-01-04 02:39:22
其不工作:(饼图即时尝试显示仍然显示几乎所有累计 – 2012-01-04 02:53:02
然后我会指出一个问题与饼图,而不是SQL或循环,我还没有饼图功能的知识 – 2012-01-04 03:03:34