非公开类Out
中的静态初始化块不运行,但运行静态嵌套类snOut
中的静态初始化块。如何以及为什么这可能?静态初始化块跳过
public class staticNested {
static{
System.out.println("In staticNested");
}
static class sn{
static{
System.out.println("sn in staticNested");
}
void p(){
System.out.println("In static nested class method p");
}
}
public static void main(String [] args){
sn n = new sn();
n.p();
Out.snOut no = new Out.snOut();
no.p();
}
}
class Out{
static{
System.out.println("In Out"); //Skips this
System.out.println("Here"); //Skips this
}
static class snOut{
static {
System.out.println("In snOut in Out");
}
private int x;
void p(){
System.out.println("In snOut in outside Class out: " + x);
}
}
}
这是输出:
In staticNested
sn in staticNested
In static nested class method p
In snOut in Out
In snOut in outside Class out: 0
我不认为班级'Out'会被加载。它在您访问其静态字段或静态方法或加载实例时加载。我的初学者知识> – jn1kk
啊。我懂了。在主要方法中创建一个新实例会使块运行。谢谢 – Mob
为什么'Out'不加载和'staticNested'确实是因为main是在'staticNested'中,它可以像你期望的那样自动加载。 – jn1kk