Twitter与SLRequest共享

这是Sam.Currently我devloping twitter份额在我的应用程序。我需要实现，没有ComposeController.I需要与社会框架SLRequest集成。这是我使用的代码是如下的Twitter与SLRequest共享

ACAccountStore *accountStore = [[ACAccountStore alloc] init]; 
ACAccountType *twitterAccountType =[accountStore accountTypeWithAccountTypeIdentifier:ACAccountTypeIdentifierTwitter]; 
[accountStore requestAccessToAccountsWithType:twitterAccountType options:NULL completion:^(BOOL granted, NSError *error) { 
    if (granted) { 
     NSLog(@"Creating Request"); 
     // Step 2: Create a request 
     NSArray *twitterAccounts =[accountStore accountsWithAccountType:twitterAccountType]; 
     NSURL *url = [NSURL URLWithString:@"https://api.twitter.com/1.0/statuses/update.json"]; 
     NSDictionary *params = @{@"screen_name" : @"naheshsamy",@"include_rts" : @"0",@"trim_user" : @"1",@"count" : @"1"}; 
     SLRequest *request = 
     [SLRequest requestForServiceType:SLServiceTypeTwitter requestMethod:SLRequestMethodGET URL:url parameters:params]; 

     // Attach an account to the request 
     [request setAccount:[twitterAccounts lastObject]]; 
     NSLog(@"Request %@",request); 
     // Step 3: Execute the request 
     [request performRequestWithHandler: ^(NSData *responseData,NSHTTPURLResponse *urlResponse,NSError *error) { 
      if (responseData) { 
       if (urlResponse.statusCode >= 200 && urlResponse.statusCode < 300) { 
        NSError *jsonError; 
        NSDictionary *timelineData = [NSJSONSerialization JSONObjectWithData:responseData options:NSJSONReadingAllowFragments error:&jsonError]; 

        if (timelineData) { 
         NSLog(@"Timeline Response: %@\n", timelineData); 
        } 
        else { 
         // Our JSON deserialization went awry 
         NSLog(@"JSON Error: %@", [jsonError localizedDescription]); 
        } 
       } 
       else { 
        // The server did not respond ... were we rate-limited? 
        NSLog(@"The response status code is %d %@ %@",urlResponse.statusCode,urlResponse.suggestedFilename,error); 
       } 
      } 
     }]; 
    } 
    else { 
     // Access was not granted, or an error occurred 
     NSLog(@"%@", [error localizedDescription]); 
    } 
}];

我一直在获取状态400错误.. 任何帮助将不胜感激。 Regards， Sam.P

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2014-09-05 MaheThiru

该代码似乎与我用过的相似。他们确实已经警告说API的版本1.0不再受支持，可能无法正常工作。尝试更改为1.1并查看它是否可以解决您的问题。

@"https://api.twitter.com/1.1/statuses/update.json"

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2014-09-05 12:12:36

感谢您的宝贵答案里拉..现在我已经与twitter API's成功分享。现在我需要知道如何与访问令牌共享没有使用默认的Twitter帐户.. – MaheThiru 2014-09-08 03:15:26

Twitter与SLRequest共享

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