用随机替换替换字符串的随机字

Question

我正在开发一个脚本，它需要一篇文章，搜索文章中的“关键字”，然后用锚链接随机替换该关键字。

我有脚本工作，因为它应该，但是我需要能够有一个“替代”的数组循环和插入随机位置。

因此，第一个随机位置将获得锚链接＃1。 第二个随机位置将获得锚链接＃2。 第三个随机位置将获得锚链接＃3。 等等

我找到了答案的一半我的问题在这里：PHP replace a random word of a string

public function replace_random ($str, $search, $replace, $n) { 

    // Get all occurences of $search and their offsets within the string 
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE); 

    // Get string length information so we can account for replacement strings that are of a different length to the search string 
    $searchLen = strlen($search); 
    $diff = strlen($replace) - $searchLen; 
    $offset = 0; 

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches 
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n); 
    foreach ($toReplace as $match) { 
     $str = substr($str, 0, $matches[0][$match][1] + $offset).$replace.substr($str, $matches[0][$match][1] + $searchLen + $offset); 
     $offset += $diff; 
    } 

    return $str; 

} 

所以我的问题是，我怎样才能改变这种功能以接受$数组替换变量？

编辑 我也试图从mt_rand，从替代品的阵列输出我更换一些随机的数组键，但它仍然是只增加整个内容替换之一。我希望函数为它找到的$ search变量的每个实例选择一个“关键字”。

public function replace_random ($str, $search, $replace, $n) { 

    // Get all occurences of $search and their offsets within the string 
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE); 

    // Get string length information so we can account for replacement strings that are of a different length to the search string 
    $searchLen = strlen($search); 
    $diff = strlen($replace) - $searchLen; 
    $offset = 0; 

    $searchCount = count($replace); 
    $arrayNum = mt_rand(0, 4); 

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches 
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n); 
    foreach ($toReplace as $match) { 
     $str = substr($str, 0, $matches[0][$match][1] + $offset).$replace[$arrayNum].substr($str, $matches[0][$match][1] + $searchLen + $offset); 
     $offset += $diff; 
    } 

    return $str; 

} 

Answer 1

的解决方案横空出世，我需要一个变量添加到foreach循环：

$replaceRand = $replace[array_rand($replace)]; 

，并调用它在$ str变量：

$str = substr($str, 0, $matches[0][$match][1] + $offset).$replaceRand.substr($str, $matches[0][$match][1] + $searchLen + $offset); 

整个代码结束up：

public function replace_random ($str, $search, $replace, $n) { 

    // Get all occurences of $search and their offsets within the string 
    $count = preg_match_all('/\b'.preg_quote($search, '/').'\b/', $str, $matches, PREG_OFFSET_CAPTURE); 

    // Get string length information so we can account for replacement strings that are of a different length to the search string 
    $searchLen = strlen($search); 
    $diff = strlen($replace) - $searchLen; 
    $offset = 0; 

    // Loop $n random matches and replace them, if $n < 1 || $n > $count, replace all matches 
    $toReplace = ($n < 1 || $n > $count) ? array_keys($matches[0]) : (array) array_rand($matches[0], $n); 
    foreach ($toReplace as $match) { 
     $replaceRand = $replace[array_rand($replace)]; 
     $str = substr($str, 0, $matches[0][$match][1] + $offset).$replaceRand.substr($str, $matches[0][$match][1] + $searchLen + $offset); 
     $offset += $diff; 
    } 

    return $str; 

}