Javascript排序关键值对象的数组

我试图对包含状态键的对象进行排序，这些对象包含“在线”，“离线”，“忙碌”状态，所以只想对数组进行排序“在线”将出现在顶部，其次是“忙”，然后选择“离线”Javascript排序关键值对象的数组

var arr = [{_id: "58e21249", name: "test2", status: "offline"}, 
      {_id: "58e1249", name: "test3", status: "online"}, 
      {_id: "58qwe49", name: "test21", status: "offline"}, 
      {_id: "58ed49", name: "test212", status: "online"}, 
      {_id: "58ee49", name: "test23", status: "offline"}, 
      {_id: "58xe49", name: "test12", status: "online"}, 
      {_id: "5849", name: "test2323", status: "busy"}, 
      {_id: "58er49", name: "test2121", status: "busy"}]; 

arr.sort(function(first, second) { 
    if (second.status == "online") return 1; 

}); 

console.log(arr);

这将返回我只有状态：“在线”的顶部。由于

来源

2017-09-28 Sagar Jagadesh

单挑：这个问题在[meta]（https://meta.stackoverflow.com/q/357183）上提及。 –

试试这个：

var arr = [{_id: "58e21249", name: "test2", status: "offline"}, 
 
      {_id: "58e1249", name: "test3", status: "online"}, 
 
      {_id: "58qwe49", name: "test21", status: "offline"}, 
 
      {_id: "58ed49", name: "test212", status: "online"}, 
 
      {_id: "58ee49", name: "test23", status: "offline"}, 
 
      {_id: "58xe49", name: "test12", status: "online"}, 
 
      {_id: "5849", name: "test2323", status: "busy"}, 
 
      {_id: "58er49", name: "test2121", status: "busy"}]; 
 
      
 
var statusOrder = ["online", "busy", "offline"]; 
 
    
 
arr = arr.sort(function(a, b) { 
 
    return statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status); 
 
}); 
 

 
console.log(arr);

甚至更短的与ECMAScript6：

var arr = [{_id: "58e21249", name: "test2", status: "offline"}, 
 
      {_id: "58e1249", name: "test3", status: "online"}, 
 
      {_id: "58qwe49", name: "test21", status: "offline"}, 
 
      {_id: "58ed49", name: "test212", status: "online"}, 
 
      {_id: "58ee49", name: "test23", status: "offline"}, 
 
      {_id: "58xe49", name: "test12", status: "online"}, 
 
      {_id: "5849", name: "test2323", status: "busy"}, 
 
      {_id: "58er49", name: "test2121", status: "busy"}]; 
 
      
 
var statusOrder = ["online", "busy", "offline"]; 
 
    
 
arr = arr.sort((a, b) => statusOrder.indexOf(a.status) - statusOrder.indexOf(b.status)); 
 

 
console.log(arr);

来源

2017-09-28 10:12:53 Faly

单挑：这个问题在[meta]（https://meta.stackoverflow.com/q/357183）上提及。 –

-1

var statusOrder = ["online", "offline", "busy"]; 
arr.sort(function(first, second) { 
    return statusOrder.indexOf(first.status) < statusOrder.indexOf(second.status); 
});

来源

2017-09-28 10:14:15 Ammar

此代码格式化您的硬盘驱动器？ – SteveFest

Javascript排序关键值对象的数组

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