使用java将节点追加到现有的XML文件

嗨，即时通讯寻找一种解决方案，将Java节点追加到现有的XML文件。我得到的是这样的使用java将节点追加到现有的XML文件

<data> 
<people> 
    <person> 
     <firstName>Frank</firstName> 
     <lastName>Erb</lastName> 
     <access>true</access> 
     <images> 
      <img>hm001.jpg</img> 
     </images> 
    </person> 
    <person> 
     <firstName>Hans</firstName> 
     <lastName>Mustermann</lastName> 
     <access>true</access> 
     <images> 
      <img>hm001.jpg</img> 
     </images> 
    </person> 
    <person> 
     <firstName>Thomas</firstName> 
     <lastName>Tester</lastName> 
     <access>false</access> 
     <images> 
      <img>tt001.jpg</img> 
     </images> 
    </person> 
</people> 
</data>

一个XML文件我whant补充的是与它的人民元素中的元素一个人节点。我的大问题是作为根节点的数据节点。如果它将作为根节点，我可以解决它。但我无法设法让人节点下的人节点。

  <person> 
     <firstName>Tom</firstName> 
     <lastName>Hanks</lastName> 
     <access>false</access> 
     <images> 
      <img>tt001.jpg</img> 
     </images> 
    </person>

感谢您的帮助！

我的Java代码看起来就这样

Element root = document.getDocumentElement(); 


// Root Element 
Element rootElement = document.getDocumentElement(); 

Collection<Server> svr = new ArrayList<Server>(); 
svr.add(new Server()); 

for (Server i : svr) { 
    // server elements 

    Element server = document.createElement("people"); 
    rootElement.appendChild(server); 
    //rootElement.appendChild(server); 

    Element name = document.createElement("person"); 
    server.appendChild(name); 

    Element firstName = document.createElement("firstName"); 
    firstName.appendChild(document.createTextNode(i.getFirstName())); 
    server.appendChild(firstName); 
    name.appendChild(firstName); 

    Element port = document.createElement("lastName"); 
    port.appendChild(document.createTextNode(i.getLastName())); 
    server.appendChild(port); 
    name.appendChild(port); 

    Element access = document.createElement("access"); 
    access.appendChild(document.createTextNode(i.getAccess())); 
    server.appendChild(access); 
    name.appendChild(access); 

    String imageName = Main.randomImgNr+""; 
    Element images = document.createElement("images"); 
    //images.appendChild(document.createTextNode(i.getAccess())); 
    Element img = document.createElement("img"); 
    img.appendChild(document.createTextNode(imageName));//i.getImage())); 
    images.appendChild(img);    

    server.appendChild(images); 
    name.appendChild(images); 
    root.appendChild(server);

来源

2014-01-20 user3216026

试过使用JAXB？它非常整齐。 –

没有一个库，你可以做这样的事情：

Element dataTag = doc.getDocumentElement(); 
Element peopleTag = (Element) dataTag.getElementsByTagName("people").item(0); 

Element newPerson = doc.createElement("person"); 

Element firstName = doc.createElement("firstName"); 
firstName.setTextContent("Tom"); 

Element lastName = doc.createElement("lastName"); 
lastName.setTextContent("Hanks"); 

newPerson.appendChild(firstName); 
newPerson.appendChild(lastName); 

peopleTag.appendChild(newPerson);

其中成员：

... 
     <person> 
      <firstName>Thomas</firstName> 
      <lastName>Tester</lastName> 
      <access>false</access> 
      <images> 
       <img>tt001.jpg</img> 
      </images> 
     </person> 
     <person> 
      <firstName>Tom</firstName> 
      <lastName>Hanks</lastName> 
     </person> 
    </people> 
</data>

来源

2014-01-20 17:52:18

完美!!!!!这是我正在寻找的。谢谢！！ – user3216026

不客气！ –

有没有可能让新节点进入正确的格式？每当我尝试添加这些节点时，它们都卡在左侧。我在这里先向您的帮助表示感谢。 –

这是很容易与JOOX库，例子：

// Parse the document from a file 
Document document = $(xmlFile).document(); 

// Find the order at index 4 and add an element "paid" 
$(document).find("people").children().eq(4).append("<paid>true</paid>"); 

// Find those orders that are paid and flag them as "settled" 
$(document).find("people").children().find("paid").after("<settled>true</settled>");

来源

2014-01-20 17:23:55 MariuszS

如果不使用库或包装器，不可能这样做吗？ – user3216026

使用库更容易。 – MariuszS

关注这个一般方法：

public static void main(String[] args) { 
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
    DocumentBuilder db = null; 
    try { 
     db = dbf.newDocumentBuilder(); 
     Document doc = db.parse("input.xml"); 
     NodeList people = doc.getElementsByTagName("people"); 
     people.item(0) 
       .appendChild(
         createPersonElement(doc, "Tom", "Hanks", true, 
           "tt001.jpg")); 
     System.out.println(nodeToString(doc)); 
    } catch (SAXException e) { 
     // handle SAXException 
    } catch (IOException e) { 
     // handle IOException 
    } catch (TransformerException e) { 
     // handle TransformerException 
    } catch (ParserConfigurationException e1) { 
     // handle ParserConfigurationException 
    } 
} 

private static Element createPersonElement(Document doc, String firstName, 
     String lastName, Boolean access, String image) { 
    Element el = doc.createElement("person"); 
    el.appendChild(createPersonDetailElement(doc, "firstName", firstName)); 
    el.appendChild(createPersonDetailElement(doc, "lastName", lastName)); 
    el.appendChild(createPersonDetailElement(doc, "access", 
      access.toString())); 
    Element images = doc.createElement("images"); 
    images.appendChild(createPersonDetailElement(doc, "img", image)); 
    el.appendChild(images); 
    return el; 
} 

private static Element createPersonDetailElement(Document doc, String name, 
     String value) { 
    Element el = doc.createElement(name); 
    el.appendChild(doc.createTextNode(value)); 
    return el; 
}

这使用以下辅助方法来打印结果：

private static String nodeToString(Node node) throws TransformerException { 
    StringWriter buf = new StringWriter(); 
    Transformer xform = TransformerFactory.newInstance().newTransformer(); 
    xform.transform(new DOMSource(node), new StreamResult(buf)); 
    return buf.toString(); 
}

这可以被修改，以更新原始文件来代替。

来源

2014-01-20 17:55:35

-1

public static void main(String[] args) throws ParserConfigurationException, IOException { 
    DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); 
    DocumentBuilder db; 
    db = null; 
    try { 
     db = dbf.newDocumentBuilder(); 
     Document doc = db.parse("input.xml"); 
     NodeList people = doc.getElementsByTagName("people"); 
     people.item(0).appendChild(createPersonElement(doc, "Tom", "Hanks", true, "tt001.jpg")); 
     Transformer transformer = TransformerFactory.newInstance().newTransformer(); 
     transformer.setOutputProperty(OutputKeys.INDENT, "yes"); 
     DOMSource source = new DOMSource(doc); 
     StreamResult console = new StreamResult(System.out);//for Console print 
     transformer.transform(source, console); 
     StreamResult file = new StreamResult(new File("input.xml")); 
     transformer.transform(source, file); 
    } catch (SAXException | IOException | TransformerException | ParserConfigurationException e) { 
     System.out.println(e); 
    } 
} 

private static Element createPersonElement(Document doc, String firstName, 
     String lastName, Boolean access, String image) { 
    Element el = doc.createElement("person"); 
    el.appendChild(createPersonDetailElement(doc, "firstName", firstName)); 
    el.appendChild(createPersonDetailElement(doc, "lastName", lastName)); 
    el.appendChild(createPersonDetailElement(doc, "access", 
      access.toString())); 
    Element images = doc.createElement("images"); 
    images.appendChild(createPersonDetailElement(doc, "img", image)); 
    el.appendChild(images); 
    return el; 
} 

private static Element createPersonDetailElement(Document doc, String name, 
     String value) { 
    Element el = doc.createElement(name); 
    el.appendChild(doc.createTextNode(value)); 
    return el; 
}

来源

2015-11-19 11:17:26

使用java将节点追加到现有的XML文件

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