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我编写的用于向000webhost上的服务器发送请求的java类不起作用。我得到不推荐的http元素,所以我的代码不会编译。我尝试过改变我的API级别,但没有任何用处,它只是阻止了我的gradle的构建。 下面是我在谈论的Java类:Android Studio中的服务器请求类
package com.mu.cs.loginregister;
import android.app.ProgressDialog;
import android.content.Context;
import android.os.AsyncTask;
import org.apache.http.params.HttpConnectionParams;
import org.apache.http.params.HttpParams;
import org.json.JSONObject;
import java.util.HashMap;
import java.util.Map;
/**
* Created by John on 10/12/2015.
*/
public class ServerRequests {
ProgressDialog progressDialog;
public static final int CONNECTION_TIMEOUT = 1000 * 15;
public static final String SERVER_ADDRESS = "http://www.thenameofmyserver.com/";
public ServerRequests(Context context){
progressDialog = new ProgressDialog(context);
progressDialog.setCancelable(false);
progressDialog.setTitle("Processing");
progressDialog.setMessage("Please wait....");
}
public void storeUserDataInBackground(User user, GetUserCallback userCallback){
progressDialog.show();
new StoreUserDataAsyncTask(user, userCallback).execute();
}
public void fetchUserDataInBackground(User user, GetUserCallback callback){
progressDialog.show();
new fetchUserDataAsyncTask(user, callback).execute();
}
public class StoreUserDataAsyncTask extends AsyncTask <Void, Void, Void>{
User user;
GetUserCallback userCallback;
public StoreUserDataAsyncTask(User user, GetUserCallback userCallback){
this.user = user;
this.userCallback = userCallback;
}
@Override
protected Void doInBackground(Void... params){
Map<String, String> dataToSend = new HashMap<>();
dataToSend.put("name", user.name);
dataToSend.put("age", user.age + "");
dataToSend.put("username", user.username);
dataToSend.put("password", user.password);
HttpParams httpRequestParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpRequestParams, CONNECTION_TIMEOUT);
HttpConnectionParams.setSoTimeout(httpRequestParams, CONNECTION_TIMEOUT);
HttpClient client = new DefaultHttpClient(httpRequestParams);
HttpPost post = new HttpPost (SERVER_ADDRESS + "Register.php");
try{
post.setEntity(new UrlEncodedFormEntity(dataToSend));
client.execute(post);
}catch (Exception e){
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void aVoid) {
progressDialog.dismiss();
userCallback.done(null);
super.onPostExecute(aVoid);
}
}
public class fetchUserDataAsyncTask extends AsyncTask<Void, Void, User>{
User user;
GetUserCallback userCallback;
public fetchUserDataAsyncTask(User user, GetUserCallback userCallback){
this.user = user;
this.userCallback = userCallback;
}
@Override
protected User doInBackground(Void... params) {
Map<String, String> dataToSend = new HashMap<>();
dataToSend.put("username", user.username);
dataToSend.put("password", user.password);
HttpParams httpRequestParams = new BasicHttpParams();
HttpConnectionParams.setConnectionTimeout(httpRequestParams, CONNECTION_TIMEOUT);
HttpConnectionParams.setSoTimeout(httpRequestParams, CONNECTION_TIMEOUT);
HttpClient client = new DefaultHttpClient(httpRequestParams);
HttpPost post = new HttpPost (SERVER_ADDRESS + "FetchUserData.php");
User returnedUser = null;
try{
post.setEntity(new UrlEncodedFormEntity(dataToSend));
HttpResponse httpResponse = client.execute(post);
HttpEntity entity = httpResponse.getEntity();
String result = EntityUtils.toString(entity);
JSONObject jObject = new JSONObject(result);
if (jObject.length() == 0){
user = null;
}else{
String name =jObject.getString("name");
int age = jObject.getInt("age");
returnedUser = new User(name, user.username);
}
}catch (Exception e){
e.printStackTrace();
}
return returnedUser;
}
@Override
protected void onPostExecute(User returnedUser){
progressDialog.dismiss();
userCallback.done(returnedUser);
super.onPostExecute(returnedUser);
}
}
}
我还写了两个PHP文件在我的数据库,该代码将与交谈存储。
PHP1:
<?php
$con=mysqli_connect("localhost","my_user","my_password","my_db");
$name=$_POST["name"];
$age=$_POST["age"];
$password=$_POST["password"];
$username=$_POST["username"];
$statement = mysqli_prepare($con, "INSERT INTO User (name, age, username, password) VALUES (?, ?, ?, ?) ");
mysqli_stmt_bind_param($statement, "siss", $name, $age, $username, $password);
mysqli_stmt_execute($statement);
mysqli_stmt_close($statment);
mysqli_close($con);
?>
PHP2:
<?php
$con=mysqli=connect("localhost","my_user","my_password","my_db);
$password = $_POST["password"];
$username = $_POST["username"];
$statement = mysqli_prepare($con, "SELECT" * FROM User WHERE username = ? AND password = ?");
mysqli_stmt_bind_param($statement, "ss", $username, $password);
mysqli_stmt_execute($statement);
mysqli_stmt_store_result($statement);
mysqli_stmt_bind_result($statment, $userID, $name, $age, $username, $password);
$user = array();
while(mysqli_stmt_fetch($statement)){
$user[name] = $name;
$user[age] = $age;
$user[username] = $username;
$user[password] = $password;
}
echo json_encode($user);
mysqli_stmt_close($con);
mysqli_close($con);
?>
与这是为什么不工作将非常感激任何帮助。谢谢
为什么不尝试使用非过时的http元素? –