我正在使用第三方wsdl创建一个Web服务,它可以帮助我获得一种通知。现在我必须将该通知保存在数据库中,并执行与数据库相关的其他几个操作。 在我的persistence.xml有两个持久性单元如下:在网络服务中使用JPA的最佳方式是什么?
<persistence-unit name="PU1" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/vsDS</jta-data-source>
<class>com.Response</class>
<class>com.Request</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="eclipselink.logging.level" value="INFO"/>
</properties>
</persistence-unit>
<persistence-unit name="PU2" transaction-type="JTA">
<provider>org.eclipse.persistence.jpa.PersistenceProvider</provider>
<jta-data-source>jdbc/vdDS</jta-data-source>
<class>com.LogRequest</class>
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<property name="eclipselink.logging.level" value="INFO"/>
</properties>
</persistence-unit>
直到我却做出了一个名为Service.java有我需要如下的DB执行所有功能类:
public class Service {
private static Logger logger = Logger.getLogger(Service.class);
private EntityManagerFactory PU1;
private EntityManagerFactory PU2;
public Service(){
System.out.println("in service's constructer");
PU1=Persistence.createEntityManagerFactory("PU1");
PU2=Persistence.createEntityManagerFactory("PU2");
}
public void logSubRequest(String msg){
EntityManager em= PU1.createEntityManager();
try{
em.getTransaction().begin();
Request req=new Request();
req.setMessage(msg);
req.setStatus("Y");
em.persist(req);
em.getTransaction().commit();
}catch(Exception e){
logger.error("In logSubRequest="+e.getMessage());
e.printStackTrace();
}finally{
if(em.isOpen()){
em.close();
}
}
}
// there are several other methods of such kind that either persist entities or executeUpdate
}
我的问题是:我用标准的方法来实现与web服务的JPA,或者我应该去一些其他的技术/方法。如果我在标准之外做任何事情,请好好建议和指导。